To solve this problem, we analyze the person's displacement, which is the straight-line distance between their starting point and their ending point after walking.

Here’s the breakdown:

1. First movement: The person walks 200 m due north.

   • Represent this as a vector pointing straight up on a graph.

2. Second movement: The person walks another 200 m in an unknown direction.

   • To analyze the maximum and minimum displacement, consider the possible angles between the two vectors.

Key Scenarios for Displacement:

1. If the person walks 200 m directly north again (same direction):

   • Total displacement = $200 + 200 = 400 \, \text{m}$.

2. If the person walks 200 m directly south (opposite direction):

   • Net displacement = $200 - 200 = 0 \, \text{m}$.

3. If the person walks 200 m at a right angle (90°):

   • Use the Pythagorean Theorem to calculate displacement.
     $\text{Displacement} = \sqrt{(200)^2 + (200)^2} = \sqrt{40000 + 40000} = \sqrt{80000} \approx 283 \, \text{m}.$

Conclusion:

The displacement depends on the direction of the second 200 m walk.

• Maximum displacement: 400 m (if both movements are in the same direction).
• Minimum displacement: 0 m (if the second movement is directly south).
• If at a right angle, the displacement is 283 m.

Would you like me to provide a diagram for clarity or explain further? Let me know!

Related Questions:

1. How do we determine displacement when multiple vectors are involved?
2. How does displacement differ from distance traveled?
3. What is the Pythagorean Theorem, and how is it applied here?
4. How can vectors be added graphically?
5. What are the properties of resultant vectors?

Tip: Always use the Pythagorean theorem for right-angled vector problems!