https://file.aiquickdraw.com/mathbot/file/1729536510332teciivrg.jpg

This problem involves finding the total displacement of a car that travels 35 km North and then 20 km East. 

Displacement is a vector quantity, which means we can use the Pythagorean theorem to find the straight-line distance from the starting point to the final position of the car.

The formula is:
\[
d = \sqrt{{(35^2 + 20^2)}}
\]
Now, let's calculate it:

\[
d = \sqrt{{35^2 + 20^2}} = \sqrt{{1225 + 400}} = \sqrt{{1625}} \approx 40.3 \, \text{km}
\]

So, the total displacement of the car is approximately **40.3 km**.

Would you like further details or clarifications?

Here are 5 related questions for practice:
1. What would the displacement be if the car traveled 30 km North and 40 km East?
2. How would you calculate displacement if the car traveled 50 km South and 30 km West?
3. What is the difference between distance and displacement in this context?
4. How would displacement change if the car returned to its starting point?
5. Can you find the angle between the displacement and the North direction?

**Tip:** Displacement is always a straight-line distance from the starting point, regardless of the path taken.

What is the total displacement of a car that travels 35 km North, then 20 km East?

Learn how to calculate the total displacement of a car that travels 35 km North and 20 km East using the Pythagorean theorem. This problem covers key geometry and vector addition concepts, suitable for students in Grades 7-9.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation