Math Problem Statement

Find the Z-transform of: (i) n cos(nθ), (ii) sin((nπ/2) + π/4), (iii) e^(-2n), (iv) a^|n|

Solution

To solve for the ZZ-transform of each given function, we can apply the ZZ-transform definitions and common properties. Here's a breakdown of each one:

1. ncos(nθ)n \cos(n\theta)

The ZZ-transform of ncos(nθ)n \cos(n\theta) can be derived using the property of the ZZ-transform of a sequence with a cosine term: Z{ncos(nθ)}=zcos(θ)+z2(zejθ)(zejθ)2Z\{n \cos(n\theta)\} = -\frac{z \cos(\theta) + z^2}{(z - e^{j\theta})(z - e^{-j\theta})^2}

2. sin(nπ2+π4)\sin\left(\frac{n\pi}{2} + \frac{\pi}{4}\right)

For this trigonometric sequence, the term inside the sine function can be simplified based on the angle addition formula. Generally, we can write: Z{sin(nπ2+π4)}=standard trigonometric seriesZ\{\sin\left(\frac{n\pi}{2} + \frac{\pi}{4}\right)\} = \text{standard trigonometric series} However, the exact ZZ-transform depends on applying the trigonometric identity in terms of a sinusoidal series expansion, which would generally yield complex expressions.

3. e2ne^{-2n}

The ZZ-transform of an exponential sequence eane^{-an} is given by: Z{e2n}=1ze2Z\{e^{-2n}\} = \frac{1}{z - e^{-2}}

4. ana^{|n|}

For ana^{|n|}, the ZZ-transform needs to consider values of nn for both positive and negative cases:

  • For n0n \geq 0: Z{an}=zzaZ\{a^n\} = \frac{z}{z - a}
  • For n<0n < 0: Z{an}=zza1Z\{a^{-n}\} = \frac{z}{z - a^{-1}}

Combining both cases would yield a more complex expression depending on whether nn is positive or negative.

Would you like to see a deeper explanation for any of these specific transforms or examples of their applications?

Follow-Up Questions

  1. How do initial conditions affect the ZZ-transform for causal systems?
  2. What is the role of the region of convergence (ROC) in determining the ZZ-transform's stability?
  3. How does the ZZ-transform differ when applied to left-sided sequences versus right-sided sequences?
  4. Can the ZZ-transform be used to solve differential equations, and if so, how?
  5. What is the inverse ZZ-transform, and how can it be used to reconstruct signals?

Tip:

When working with trigonometric functions in the ZZ-domain, using Euler's formulas for sine and cosine can simplify the process by converting the terms into exponential forms.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Z-transform
Trigonometric functions
Exponential sequences
Absolute value sequences

Formulas

Z{n cos(nθ)} = -((z cos(θ) + z^2) / ((z - e^(jθ))(z - e^(-jθ))^2))
Z{sin((nπ/2) + π/4)} using trigonometric series expansion
Z{e^(-2n)} = 1 / (z - e^(-2))
Z{a^|n|} considering n ≥ 0: Z{a^n} = z / (z - a), and n < 0: Z{a^(-n)} = z / (z - a^(-1))

Theorems

Z-transform properties
Euler's formula for trigonometric functions

Suitable Grade Level

University level