Math Problem Statement

Question Number: 5 A, B and C can do a piece of work in 10 days, 15 days and 30 days respectively. (a) In 1 day, how much work can be done by A and B? Answer: 1/6 part. (b) In how many days they together can finish the work? Answer: 5 days. (c) If after 3 days A left the work unfinished, in how many days the whole work will be finished? Answer: 7 days.

Solution

Let's solve the problem step by step.

Given:

  • A can complete the work in 10 days.
  • B can complete the work in 15 days.
  • C can complete the work in 30 days.

Let's calculate their daily work rates:

  • Work rate of A = 110\frac{1}{10} work/day
  • Work rate of B = 115\frac{1}{15} work/day
  • Work rate of C = 130\frac{1}{30} work/day

(a) In 1 day, how much work can be done by A and B?

The combined work rate of A and B: Work rate of A and B=110+115\text{Work rate of A and B} = \frac{1}{10} + \frac{1}{15}

Finding the common denominator (which is 30): 110=330,115=230\frac{1}{10} = \frac{3}{30}, \quad \frac{1}{15} = \frac{2}{30} 110+115=330+230=530=16\frac{1}{10} + \frac{1}{15} = \frac{3}{30} + \frac{2}{30} = \frac{5}{30} = \frac{1}{6}

Therefore, A and B together can do 16\frac{1}{6} of the work in 1 day.

Answer: 16\frac{1}{6} part

(b) In how many days can they together finish the work?

The combined work rate of A, B, and C: 110+115+130\frac{1}{10} + \frac{1}{15} + \frac{1}{30} Finding the common denominator (which is 30): 110=330,115=230,130=130\frac{1}{10} = \frac{3}{30}, \quad \frac{1}{15} = \frac{2}{30}, \quad \frac{1}{30} = \frac{1}{30} 110+115+130=330+230+130=630=15\frac{1}{10} + \frac{1}{15} + \frac{1}{30} = \frac{3}{30} + \frac{2}{30} + \frac{1}{30} = \frac{6}{30} = \frac{1}{5}

So, A, B, and C together can complete 15\frac{1}{5} of the work per day.

The total time to finish the work together is: 115=5 days\frac{1}{\frac{1}{5}} = 5 \text{ days}

Answer: 5 days

(c) If after 3 days A left the work unfinished, in how many days will the whole work be finished?

First, let's find out how much work is done in the first 3 days by A, B, and C together.

The work rate of A, B, and C together is 15\frac{1}{5} per day. Therefore, in 3 days, they will complete: 3×15=353 \times \frac{1}{5} = \frac{3}{5}

The remaining work is: 135=251 - \frac{3}{5} = \frac{2}{5}

Now, A leaves, so only B and C are working together. Their combined work rate: 115+130\frac{1}{15} + \frac{1}{30} Finding the common denominator (which is 30): 115=230,130=130\frac{1}{15} = \frac{2}{30}, \quad \frac{1}{30} = \frac{1}{30} 115+130=230+130=330=110\frac{1}{15} + \frac{1}{30} = \frac{2}{30} + \frac{1}{30} = \frac{3}{30} = \frac{1}{10}

B and C together can complete 110\frac{1}{10} of the work per day.

The time to complete the remaining 25\frac{2}{5} of the work is: 25110=2×2=4 days\frac{\frac{2}{5}}{\frac{1}{10}} = 2 \times 2 = 4 \text{ days}

Thus, the total time to finish the entire work is: 3+4=7 days3 + 4 = 7 \text{ days}

Answer: 7 days

Summary:

  • (a) 16\frac{1}{6} part
  • (b) 5 days
  • (c) 7 days

Would you like any further details or clarifications?

5 Related Questions:

  1. How much work can A and C complete together in 1 day?
  2. If only B and C work together, in how many days will they complete the work?
  3. What fraction of the work will be completed if A and B work together for 4 days?
  4. How many days will A alone take to complete half the work?
  5. If C works for 5 days alone, how much work is left to complete?

Tip

Always break down combined work problems by calculating the individual work rates first and then summing them up!

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Math Problem Analysis

Mathematical Concepts

Work and Time
Rates
Fractional Work

Formulas

Work rate of a person = 1 / (Number of days to complete the work)
Combined work rate = Sum of individual work rates
Total time to finish = 1 / (Combined work rate)

Theorems

Work Rate Theorem
Addition of Fractions

Suitable Grade Level

Grades 8-10