Math Problem Statement

A and B can complete a task in 12 days, while B and C can complete it in 16 days. If A, B, and C together complete the task in 8 days, how long will it take A and C together to complete the task?

Solution

Let's break down the problem systematically.

Step 1: Define the rates at which each person works.

  • Let AA's rate of work be aa (portion of the task completed per day).
  • Let BB's rate of work be bb.
  • Let CC's rate of work be cc.

We are given:

  1. AA and BB together can complete the task in 12 days, so their combined rate is: a+b=112a + b = \frac{1}{12}
  2. BB and CC together can complete the task in 16 days, so their combined rate is: b+c=116b + c = \frac{1}{16}
  3. AA, BB, and CC together can complete the task in 8 days, so their combined rate is: a+b+c=18a + b + c = \frac{1}{8}

Step 2: Solve for the individual rates.

We have the following system of equations:

  1. a+b=112a + b = \frac{1}{12}
  2. b+c=116b + c = \frac{1}{16}
  3. a+b+c=18a + b + c = \frac{1}{8}

From equation 3, we can substitute a+ba + b from equation 1: a+b+c=18    112+c=18a + b + c = \frac{1}{8} \implies \frac{1}{12} + c = \frac{1}{8} Solving for cc: c=18112=3224=124c = \frac{1}{8} - \frac{1}{12} = \frac{3 - 2}{24} = \frac{1}{24}

Now that we know c=124c = \frac{1}{24}, substitute this into equation 2: b+c=116    b+124=116b + c = \frac{1}{16} \implies b + \frac{1}{24} = \frac{1}{16} Solving for bb: b=116124=3248=148b = \frac{1}{16} - \frac{1}{24} = \frac{3 - 2}{48} = \frac{1}{48}

Finally, substitute b=148b = \frac{1}{48} into equation 1: a+b=112    a+148=112a + b = \frac{1}{12} \implies a + \frac{1}{48} = \frac{1}{12} Solving for aa: a=112148=4148=348=116a = \frac{1}{12} - \frac{1}{48} = \frac{4 - 1}{48} = \frac{3}{48} = \frac{1}{16}

Step 3: Find the combined rate of AA and CC.

Now that we know a=116a = \frac{1}{16} and c=124c = \frac{1}{24}, the combined rate of AA and CC is: a+c=116+124=3+248=548a + c = \frac{1}{16} + \frac{1}{24} = \frac{3 + 2}{48} = \frac{5}{48}

Step 4: Calculate the time for AA and CC to complete the task.

The time taken for AA and CC to complete the task is the reciprocal of their combined rate: Time=1a+c=1548=485=9.6days\text{Time} = \frac{1}{a + c} = \frac{1}{\frac{5}{48}} = \frac{48}{5} = 9.6 \, \text{days}

Thus, AA and CC together will take 9.6 days to complete the task.

Would you like more details on any step?

Related Questions:

  1. How can we generalize this method to more complex work problems?
  2. What happens if A and C together had a different working efficiency?
  3. How does the concept of rates apply to other areas like speed and distance?
  4. What if all workers take breaks, how do we factor that in?
  5. How do we solve a work problem when the rates are in different units?

Tip: Always break down work problems by focusing on individual rates and using the total time as the sum of rates.

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Math Problem Analysis

Mathematical Concepts

Algebra
Work and Time
Rate of Work

Formulas

Rate of work = 1 / time
Combined rate of work for two or more workers = sum of individual rates
Time to complete task = 1 / combined rate

Theorems

Basic principles of work and rate problems

Suitable Grade Level

Grades 8-10