Math Problem Statement

A, B,C started working on a project , but A left the work 9 days before the completion,and B left the work 7 days before the completion , if had A worked for 1 more day the total work would have been completed 2 days before actual time, if B would have worked for 2 more days , the total work would have been completed 3 days before the actual time, In how many days A,B,C can together finish a work if C can alone complete the work in 18 days?

Solution

Let’s define the variables for the rate of work for each person:

  • rAr_A = Rate at which A works (in work per day)
  • rBr_B = Rate at which B works (in work per day)
  • rCr_C = Rate at which C works (in work per day)

We know that C can complete the entire work in 18 days, so: rC=118r_C = \frac{1}{18}

Let TT be the total number of days it took to complete the work. From the problem, we know:

  • A worked for T9T - 9 days.
  • B worked for T7T - 7 days.
  • C worked for the entire TT days.

The total work done by A, B, and C is equal to 1 (since the whole project is completed). Thus, the total work equation can be written as: (T9)rA+(T7)rB+TrC=1(T-9)r_A + (T-7)r_B + T r_C = 1

We are also given two conditions about finishing the project earlier:

  1. If A had worked for 1 more day (total T8T - 8 days), the project would have finished 2 days earlier (i.e., in T2T - 2 days): (T8)rA+(T7)rB+(T2)rC=1(T-8)r_A + (T-7)r_B + (T-2) r_C = 1
  2. If B had worked for 2 more days (total T5T - 5 days), the project would have finished 3 days earlier (i.e., in T3T - 3 days): (T9)rA+(T5)rB+(T3)rC=1(T-9)r_A + (T-5)r_B + (T-3)r_C = 1

We now have three equations:

  1. (T9)rA+(T7)rB+TrC=1(T-9)r_A + (T-7)r_B + T r_C = 1
  2. (T8)rA+(T7)rB+(T2)rC=1(T-8)r_A + (T-7)r_B + (T-2)r_C = 1
  3. (T9)rA+(T5)rB+(T3)rC=1(T-9)r_A + (T-5)r_B + (T-3)r_C = 1

We’ll solve these equations to find the rates of A and B, and then determine how long A, B, and C together would take to complete the project.

Let me calculate this for you.The solution to the system of equations is:

  • T=10.33T = 10.33 days (approximately 10 days and 8 hours to complete the project),
  • rA=19r_A = \frac{1}{9}, meaning A can complete the work in 9 days if working alone,
  • rB=112r_B = \frac{1}{12}, meaning B can complete the work in 12 days if working alone.

Now, to find how long A, B, and C together can complete the work, we sum their rates: Total rate=rA+rB+rC=19+112+118\text{Total rate} = r_A + r_B + r_C = \frac{1}{9} + \frac{1}{12} + \frac{1}{18}

Let me calculate that.A, B, and C can together complete the entire work in 4 days.

Would you like further clarification on any part of this? Here are some related questions for deeper exploration:

  1. How can we calculate individual contributions to

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Math Problem Analysis

Mathematical Concepts

Work and Time
Algebra
System of Equations

Formulas

Work done = Rate × Time
(T-9)r_A + (T-7)r_B + T r_C = 1
(T-8)r_A + (T-7)r_B + (T-2)r_C = 1
(T-9)r_A + (T-5)r_B + (T-3)r_C = 1
Total Rate = r_A + r_B + r_C

Theorems

Equation Solving
Algebraic Manipulation

Suitable Grade Level

Grades 10-12