a box is being pushed to the right with the force of 10N. There is a frictional force of 4N on the box. The box gets pushed over a distance of 10m. Determine the work due to the person pushing.

To determine the work done by the person pushing the box, we can use the formula for work:

\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]

where:
- **Force** is the force applied by the person,
- **Distance** is the distance over which the force is applied,
- \(\theta\) is the angle between the force and the direction of motion.

In this problem:
- The applied force is \(10 \, \text{N}\),
- The distance over which the box is pushed is \(10 \, \text{m}\),
- The angle \(\theta\) is \(0^\circ\) because the force is applied in the direction of motion.

Since \(\cos(0^\circ) = 1\), the work done by the person is:

\[
\text{Work} = 10 \, \text{N} \times 10 \, \text{m} \times 1 = 100 \, \text{J}
\]

### Answer:
The work done by the person pushing the box is \(100 \, \text{J}\).

Would you like to explore more details about this solution or have any questions? Here are some related questions that might be helpful:

1. How do you calculate the net work done on the box, taking friction into account?
2. What is the significance of the angle \(\theta\) in calculating work?
3. How does friction affect the net force on the box in this scenario?
4. If the person applied a force at an angle, how would the work calculation change?
5. What would happen to the work done if the distance was doubled?

**Tip:** When calculating work, always ensure that the force and distance are in the same direction, or consider the angle between them if they’re not.

A box is being pushed to the right with the force of 10N. There is a frictional force of 4N on the box. The box gets pushed over a distance of 10m. Determine the work due to the person pushing.

Explore how to calculate the work done when pushing a box with a force of 10N over a distance of 10m. This problem involves understanding the concept of work in physics, including the formula and the role of angle in the calculation.

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