Let's solve the problems shown in the image one by one using the formula for work, which is:

$\text{Work} = \text{Force} \times \text{Distance}$

Problem 3.016:

• Max and Keisha each applied 100 newtons of force to move a dresser 3 meters.
• Total force = $100 \, \text{N} + 100 \, \text{N} = 200 \, \text{N}$
• Distance = 3 meters

$\text{Work} = 200 \, \text{N} \times 3 \, \text{m} = 600 \, \text{joules}$

Problem 3.017:

• A crane lifts a large metal beam 5 meters with a force of 5000 newtons.
• Force = 5000 newtons
• Distance = 5 meters

$\text{Work} = 5000 \, \text{N} \times 5 \, \text{m} = 25,000 \, \text{joules}$

Problem 3.018:

• Janet uses 40 newtons of force to pull a wagon 4.5 meters.
• Force = 40 newtons
• Distance = 4.5 meters

$\text{Work} = 40 \, \text{N} \times 4.5 \, \text{m} = 180 \, \text{joules}$

Would you like a more detailed explanation of any of these calculations?

Here are 5 related questions to consider:

1. How would the work change if Max and Keisha applied different forces?
2. What is the significance of the direction of force in calculating work?
3. What happens if Janet pulls the wagon over a longer distance but with the same force?
4. How does the angle between the force and distance affect the calculation of work?
5. Can work be negative? In what scenario would that occur?

Tip: Always ensure the force and distance are in the same direction when calculating work; otherwise, you may need to consider components of the force.