https://file.aiquickdraw.com/mathbot/file/1731006778794e486n8xw.jpg

To solve this problem, we can use the formula for work:

\[
W = F \times d
\]

where:
- \( W \) is the work done,
- \( F \) is the force applied,
- \( d \) is the distance over which the force is applied.

### Given Data:
- Force, \( F = 50 \, \text{N} \)
- Distance, \( d = 10 \, \text{m} \)

### Calculation:
\[
W = 50 \, \text{N} \times 10 \, \text{m} = 500 \, \text{J}
\]

Thus, the work done by the person on the cart is \( \mathbf{500 \, J} \).

### Correct Answer:
**B. 500 J**

Would you like more details on the calculation or have any questions?

Here are some related questions to expand your understanding:
1. What would happen to the work done if the force applied was doubled?
2. How is work affected if the distance covered was halved?
3. Can work be negative, and under what conditions would that occur?
4. What is the relationship between work and energy in physics?
5. How is work different from power, and how can they be calculated together?

**Tip:** Remember that work is calculated only when force is applied in the direction of motion.

A person pushes a shopping cart with a force of 50 N along a flat surface for a distance of 10 meters. How much work is done by the person on the cart?

Learn how to calculate the work done by a person pushing a shopping cart with a 50 N force over a distance of 10 meters. This problem demonstrates key physics concepts, including the work-energy principle and the formula for work. Ideal for students in Grades 6-8.

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