Math Problem Statement
Solution
Let's solve the problem together. First, we need to calculate Courtney's walking rate (miles per hour) for both days and verify if they are consistent to assume a constant rate.
Step 1: Calculate her walking rate for both days
Yesterday:
- Distance = 2.4 miles
- Time = 45 minutes = hours
- Walking rate = miles per hour
Today:
- Distance = 2.8 miles
- Time = 52.5 minutes = hours
- Walking rate = miles per hour
Since the walking rates for both days are the same (), we can conclude that Courtney walks at a constant rate.
Step 2: Analyze the question
The question asks about the relationship between walking time and distance. If Courtney walks at , then:
- Walking for 1 hour covers
- Walking 1 mile takes hours (or about 18.75 minutes)
Now evaluate the options:
-
A: "An additional 3.2 hours of walking is associated with an additional mile walked."
Incorrect. Walking 1 mile takes much less time (about 0.3125 hours). -
B: "An additional hour of walking is associated with an additional 3.2 miles walked."
Correct. Walking for 1 hour covers exactly . -
C: "An additional hour of walking is associated with an additional 0.7 mile walked."
Incorrect. 1 hour corresponds to 3.2 miles, not 0.7 miles. -
D: "An additional 0.7 hour of walking is associated with an additional mile walked."
Incorrect. Walking 1 mile takes 0.3125 hours, not 0.7 hours.
Final Answer:
B. An additional hour of walking is associated with an additional 3.2 miles walked.
Would you like further details or help understanding any step?
Expanding Questions:
- How can you calculate the walking rate from time and distance?
- What is the relationship between time, distance, and speed in general?
- If Courtney walked for 2 hours, how far would she travel?
- How do you convert minutes into hours accurately?
- Why is it important to verify the assumption of a constant walking rate?
Tip:
Always double-check units (e.g., converting minutes to hours) to ensure accurate calculations.
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Math Problem Analysis
Mathematical Concepts
Rate and Speed
Proportional Reasoning
Distance-Time Relationship
Formulas
Speed = Distance ÷ Time
Theorems
Constant Rate Relationship
Suitable Grade Level
Grades 6-8
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