Let's break this down into a mathematical equation to find Aaron's walking rate. We know the following:

• Aaron can ride 15 km in the same time it takes him to walk 7 km.
• His biking rate is 5 km/h faster than his walking rate.

Let the walking rate be $w$ (in km/h). Then, his biking rate will be $w + 5$ km/h.

The time it takes to travel a distance is given by the formula:

$\text{Time} = \frac{\text{Distance}}{\text{Rate}}$

For walking, the time it takes him to walk 7 km is:

$\text{Time walking} = \frac{7}{w}$

For biking, the time it takes him to bike 15 km is:

$\text{Time biking} = \frac{15}{w + 5}$

Since the time taken for both activities is the same:

$\frac{7}{w} = \frac{15}{w + 5}$

We can now solve this equation for $w$ (walking rate).

First, cross-multiply:

$7(w + 5) = 15w$

Expanding the left side:

$7w + 35 = 15w$

Now, solve for $w$:

$35 = 15w - 7w$ $35 = 8w$ $w = \frac{35}{8} = 4.375 \text{ km/h}$

Thus, Aaron's walking rate is 4.375 km/h.

Would you like more details or help with another problem?

Here are some related questions for further practice:

1. If Aaron rides 20 km instead of 15 km, how fast would he walk?
2. How would the solution change if the distance walked was 10 km instead of 7 km?
3. If the biking rate was 3 km/h faster than the walking rate, what would the walking speed be?
4. What is the time it takes Aaron to walk 7 km at his walking rate?
5. If the walking distance was doubled, how would that affect the biking time?

Tip: Always double-check units when solving distance, rate, and time problems to ensure consistency.