Let's move on to **Question 7**.

### **Question 7: Vertical Motion Under Gravity**

A tennis ball is thrown vertically upwards with an initial velocity of **6 m/s** from a point that is **1.5 m** above the ground.

#### **7.1 Calculate the maximum height that the tennis ball reaches above the ground.**

To calculate the maximum height, we use the **kinematic equation** for vertical motion under constant acceleration (gravity):
\[
v_f^2 = v_i^2 + 2a \Delta y
\]
Where:
- \( v_f = 0 \, \text{m/s} \) (final velocity at the highest point),
- \( v_i = 6 \, \text{m/s} \) (initial velocity),
- \( a = -9.8 \, \text{m/s}^2 \) (acceleration due to gravity, negative because it's acting downward),
- \( \Delta y \) is the displacement (height reached above the initial position).

Rearranging the equation to solve for \( \Delta y \):
\[
0 = (6)^2 + 2(-9.8) \Delta y
\]
\[
0 = 36 - 19.6 \Delta y
\]
\[
19.6 \Delta y = 36
\]
\[
\Delta y = \frac{36}{19.6} \approx 1.84 \, \text{m}
\]

The ball reaches **1.84 m** above its starting point.

Since the ball started from a height of **1.5 m** above the ground, the total maximum height \( h

Question 7: A tennis ball is thrown vertically upwards with an initial velocity of 6 m/s from a point that is 1.5 m above the ground. Calculate the maximum height that the tennis ball reaches above the ground.

Learn how to calculate the maximum height reached by a tennis ball thrown vertically with an initial velocity of 6 m/s from 1.5 m above the ground. This problem uses kinematic equations to solve vertical motion under gravity, perfect for students in Grades 9-12.

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