Math Problem Statement

Given the vectors <3, 4, 5> and B<-3, 5, -6> find A+B, A-B, and B-A

Solution

Let's calculate the vector operations one by one for vectors A=3,4,5\mathbf{A} = \langle 3, 4, 5 \rangle and B=3,5,6\mathbf{B} = \langle -3, 5, -6 \rangle.

1. A+B\mathbf{A} + \mathbf{B}

To add two vectors, add their corresponding components:

A+B=3+(3),4+5,5+(6)\mathbf{A} + \mathbf{B} = \langle 3 + (-3), 4 + 5, 5 + (-6) \rangle

A+B=0,9,1\mathbf{A} + \mathbf{B} = \langle 0, 9, -1 \rangle

2. AB\mathbf{A} - \mathbf{B}

To subtract vector B\mathbf{B} from vector A\mathbf{A}, subtract their corresponding components:

AB=3(3),45,5(6)\mathbf{A} - \mathbf{B} = \langle 3 - (-3), 4 - 5, 5 - (-6) \rangle

AB=6,1,11\mathbf{A} - \mathbf{B} = \langle 6, -1, 11 \rangle

3. BA\mathbf{B} - \mathbf{A}

To subtract vector A\mathbf{A} from vector B\mathbf{B}, subtract their corresponding components:

BA=33,54,65\mathbf{B} - \mathbf{A} = \langle -3 - 3, 5 - 4, -6 - 5 \rangle

BA=6,1,11\mathbf{B} - \mathbf{A} = \langle -6, 1, -11 \rangle

Summary of results:

  • A+B=0,9,1\mathbf{A} + \mathbf{B} = \langle 0, 9, -1 \rangle
  • AB=6,1,11\mathbf{A} - \mathbf{B} = \langle 6, -1, 11 \rangle
  • BA=6,1,11\mathbf{B} - \mathbf{A} = \langle -6, 1, -11 \rangle

Would you like more details, or do you have any questions?

Here are 5 related questions for further exploration:

  1. What is the magnitude of vector A\mathbf{A}?
  2. How do you calculate the dot product of two vectors?
  3. What is the result of the cross product A×B\mathbf{A} \times \mathbf{B}?
  4. How can you find the angle between vectors A\mathbf{A} and B\mathbf{B}?
  5. What is the projection of vector A\mathbf{A} onto vector B\mathbf{B}?

Tip: When performing vector operations, always ensure you are matching the correct components to avoid sign errors in your calculations.

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Math Problem Analysis

Mathematical Concepts

Vectors
Vector Addition
Vector Subtraction

Formulas

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Theorems

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Suitable Grade Level

High School