Math Problem Statement


  1. If (pvQ) (RR) is True , then the truth value of a)RQ is-----

                                                                                  b)PR is-----  
    
                                                                                      c)(QR)R is---------
    
                                                                                     d)(QR)P is-----
    

Solution

Given that (¬pQ)(R¬R)(\neg p \lor Q) \Rightarrow (R \land \neg R) is true, we need to determine the truth values of the statements RQR \Rightarrow Q, P¬RP \land \neg R, (QR)R(Q \Rightarrow R) \land R, and (QR)P(Q \land R) \Rightarrow P.

Step 1: Analyze the statement (¬pQ)(R¬R)(\neg p \lor Q) \Rightarrow (R \land \neg R)

First, notice that the expression R¬RR \land \neg R represents a contradiction because RR and ¬R\neg R cannot both be true simultaneously. A contradiction is always false. Thus, R¬RR \land \neg R is false.

For the conditional statement (¬pQ)(R¬R)(\neg p \lor Q) \Rightarrow (R \land \neg R) to be true, the antecedent ¬pQ\neg p \lor Q must be false. This is because a conditional statement with a false consequent (which we have here) is true only when the antecedent is false.

Step 2: Analyze ¬pQ\neg p \lor Q

The disjunction ¬pQ\neg p \lor Q is false only when both ¬p\neg p and QQ are false.

  • ¬p\neg p is false implies PP is true.
  • QQ is false.

So, we have:

  • PP is true.
  • QQ is false.
  • RR can be either true or false (since R¬RR \land \neg R forces no specific value on RR).

Step 3: Determine the truth values for each statement

a) RQR \Rightarrow Q:

RQR \Rightarrow Q is true if RR is false or QQ is true. Since QQ is false, the truth value of RQR \Rightarrow Q depends on RR:

  • If RR is true, RQR \Rightarrow Q is false.
  • If RR is false, RQR \Rightarrow Q is true.

b) P¬RP \land \neg R:

P¬RP \land \neg R is true if both PP is true and ¬R\neg R is true (i.e., RR is false). Since PP is true:

  • If RR is true, P¬RP \land \neg R is false.
  • If RR is false, P¬RP \land \neg R is true.

c) (QR)R(Q \Rightarrow R) \land R:

QRQ \Rightarrow R is true if QQ is false (which it is) or RR is true. Since QQ is false, QRQ \Rightarrow R is true regardless of RR.

  • If RR is true, (QR)R(Q \Rightarrow R) \land R is true.
  • If RR is false, (QR)R(Q \Rightarrow R) \land R is false.

d) (QR)P(Q \land R) \Rightarrow P:

QRQ \land R is true only if both QQ and RR are true. Since QQ is false, QRQ \land R is false, and the conditional (QR)P(Q \land R) \Rightarrow P is true regardless of PP.

Summary of Truth Values:

The truth values depend on whether RR is true or false:

  • If RR is true:

    • a) RQR \Rightarrow Q is false.
    • b) P¬RP \land \neg R is false.
    • c) (QR)R(Q \Rightarrow R) \land R is true.
    • d) (QR)P(Q \land R) \Rightarrow P is true.
  • If RR is false:

    • a) RQR \Rightarrow Q is true.
    • b) P¬RP \land \neg R is true.
    • c) (QR)R(Q \Rightarrow R) \land R is false.
    • d) (QR)P(Q \land R) \Rightarrow P is true.

Would you like further clarification or have any questions?


  1. What does it mean when a conditional statement has a contradiction as a consequent?
  2. How does the truth value of a disjunction work?
  3. Can you explain why a conditional statement with a false antecedent is always true?
  4. What are the conditions under which a conjunction is true?
  5. How do the truth values of implications depend on the antecedent and consequent?

Tip: When solving logic problems, carefully determine the truth values of individual components before combining them into larger expressions.

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Math Problem Analysis

Mathematical Concepts

Logic
Truth Tables
Conditional Statements

Formulas

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Theorems

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Suitable Grade Level

Grades 10-12