Math Problem Statement

  1. If (pQ)(SvR) is false, then the truth value of a)SR is----

                                                                             b)PvS is-----
    
                                                                                c)(PQ)R is--------
    
                                                                                d)PR is-------
    

Solution

Given that (pQ)(¬SR)(p \land Q) \Rightarrow (\neg S \lor R) is false, we can determine the truth values of the statements SRS \Rightarrow R, ¬P¬S\neg P \lor \neg S, (P¬Q)R(P \land \neg Q) \Leftrightarrow R, and PRP \land R as follows:

Step 1: Analyze the statement (pQ)(¬SR)(p \land Q) \Rightarrow (\neg S \lor R)

A conditional statement ABA \Rightarrow B is false only when AA is true and BB is false.

So, for (pQ)(¬SR)(p \land Q) \Rightarrow (\neg S \lor R) to be false:

  • pQp \land Q must be true (i.e., pp is true and QQ is true).
  • ¬SR\neg S \lor R must be false.

Step 2: Analyze ¬SR\neg S \lor R

The disjunction ¬SR\neg S \lor R is false only when both ¬S\neg S and RR are false.

  • ¬S\neg S is false implies SS is true.
  • RR is false.

So, we have:

  • SS is true.
  • RR is false.
  • pp is true.
  • QQ is true.

Step 3: Determine the truth values for each statement

a) SRS \Rightarrow R:

SRS \Rightarrow R is true if SS is false or RR is true. Since SS is true and RR is false, the statement SRS \Rightarrow R is false.

b) ¬P¬S\neg P \lor \neg S:

¬P¬S\neg P \lor \neg S is true if either ¬P\neg P or ¬S\neg S is true. Given PP is true and SS is true, ¬P\neg P is false and ¬S\neg S is false. Therefore, ¬P¬S\neg P \lor \neg S is false.

c) (P¬Q)R(P \land \neg Q) \Leftrightarrow R:

P¬QP \land \neg Q would be false since QQ is true. RR is false. The equivalence (P¬Q)R(P \land \neg Q) \Leftrightarrow R will be true since both sides are false.

d) PRP \land R:

PRP \land R is true if both PP and RR are true. Since PP is true and RR is false, PRP \land R is false.

Summary of Truth Values:

a) SRS \Rightarrow R is false.
b) ¬P¬S\neg P \lor \neg S is false.
c) (P¬Q)R(P \land \neg Q) \Leftrightarrow R is true.
d) PRP \land R is false.

Would you like more details or have any questions?


  1. What is the truth table for a conditional statement?
  2. How does the truth value of a conjunction work?
  3. Can you explain the negation of a disjunction?
  4. What is the biconditional operation in logic?
  5. How does one determine the truth value of complex logical statements?

Tip: When dealing with logical statements, it's essential to carefully consider the conditions under which compound statements are true or false.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Logic
Conditional Statements
Disjunction
Conjunction
Equivalence

Formulas

-

Theorems

-

Suitable Grade Level

High School