Math Problem Statement

why is it a straight line decreasing from -1 to -7

Solution

You're right to question that! My earlier explanation contained a mistake in evaluating the function. Let's correct it.

Correct Analysis of the Function f(t)=[u(t2)u(t5)](32t)f(t) = \left[ u(t-2) - u(t-5) \right](3 - 2t)

Step 1: Understand the Function's Structure

  1. Unit Step Function u(ta)u(t-a):

    • u(t2)u(t-2) activates at t=2t = 2.
    • u(t5)u(t-5) activates at t=5t = 5.
  2. Expression u(t2)u(t5)u(t-2) - u(t-5):

    • This expression equals 1 when 2t<52 \leq t < 5 and 0 elsewhere.

Step 2: Simplify the Function

  • For t<2t < 2, both u(t2)u(t-2) and u(t5)u(t-5) are 0, so f(t)=0f(t) = 0.
  • For 2t<52 \leq t < 5, u(t2)=1u(t-2) = 1 and u(t5)=0u(t-5) = 0, so f(t)=32tf(t) = 3 - 2t.
  • For t5t \geq 5, both u(t2)u(t-2) and u(t5)=1u(t-5) = 1, so f(t)=0f(t) = 0.

Step 3: Evaluate f(t)f(t) within 2t<52 \leq t < 5

In the interval 2t<52 \leq t < 5: f(t)=32tf(t) = 3 - 2t

This is a linear equation:

  • At t=2t = 2: f(2)=32(2)=34=1f(2) = 3 - 2(2) = 3 - 4 = -1
  • At t=5t = 5: f(5)=32(5)=310=7f(5) = 3 - 2(5) = 3 - 10 = -7

Thus, the line decreases from 1-1 at t=2t = 2 to 7-7 at t=5t = 5.

Final Graph:

  • The graph is 00 for t<2t < 2 and t5t \geq 5.
  • For 2t<52 \leq t < 5, the graph is a straight line with a negative slope, decreasing from 1-1 at t=2t = 2 to 7-7 at t=5t = 5.

So, the function 32t3 - 2t is linear with a negative slope, which explains why the graph decreases linearly from 1-1 to 7-7 as tt increases from 2 to 5.

Let me know if you need any further clarification or details on this! Would you like me to provide additional examples or explanations?

Related Questions:

  1. How can the slope of a linear function affect its graph?
  2. What would happen if the coefficient of tt were positive in the linear term?
  3. How can the piecewise definition be extended to model more complex behaviors?
  4. What other functions can be modified by unit step functions to create piecewise linear graphs?
  5. How can we analyze the discontinuity at points where the unit step function changes?

Tip:

When analyzing functions that involve unit step functions, always carefully evaluate the function within each interval defined by the step points. This ensures accurate graphing and understanding of the function's behavior.

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Math Problem Analysis

Mathematical Concepts

Unit Step Function
Piecewise Linear Functions
Linear Equations

Formulas

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Theorems

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Suitable Grade Level

Advanced High School