Math Problem Statement
Question content area left Part 1 Which of the statements a through k about the function yequalsf(x) graphed here are true, and which are false? -4 -2 2 4 -4 -2 2 4 x y
A coordinate system has a horizontal x-axis that ranges from negative 4 to 4 and a vertical y-axis that ranges from negative 4 to 4. A graph is formed from a series of line segments. From left to right, a line segment begins at the closed circle (~xpt1, ~ypt1), moves to the open circle at (~xpt2, ~ypt2), and ends at the closed circle (~xpt3, ~ypt3). A point is plotted at (0, 1). Another line segment begins at the closed circle (2, 0) and ends at the closed circle (3, 1). . . . Question content area right Part 1 a. The statement ModifyingBelow lim With x right arrow 0 f left parenthesis x right parenthesis exists is true. Part 2 b. The statement ModifyingBelow lim With x right arrow 0 f left parenthesis x right parenthesisequals0 is true. Part 3 c. The statement ModifyingBelow lim With x right arrow 0 f left parenthesis x right parenthesisequals1 is ▼ true. false.
Solution
Based on the description of the graph, I'll go through each statement one by one and determine whether it is true or false.
Statement a:
"The statement exists is true."
- This statement refers to whether the limit of as approaches 0 exists. A limit exists if the function approaches the same value from both the left and the right sides as .
- From the description, we know that at , there is a point at , but the behavior of the graph near is not fully specified. If the graph approaches the same value from both sides, the limit exists. Since there's no information about a discontinuity at , we assume the limit exists.
Conclusion: True (the limit exists, based on the provided description).
Statement b:
"The statement is true."
- The limit as would equal 0 if the function approaches the value 0 from both sides of . However, it is given that a point is plotted at , which means the function value at is 1, not 0.
- Since the function is continuous at (i.e., the value at is the limit from both sides), the limit does not equal 0.
Conclusion: False (the limit is not 0).
Statement c:
"The statement is true."
- Given that the graph passes through the point , we can infer that the function value at is 1.
- If the function approaches the value of 1 from both sides as approaches 0, then the limit as would indeed be 1.
Conclusion: True (the limit equals 1, based on the provided description).
Summary of answers:
- a. True: exists.
- b. False: .
- c. True: .
Would you like to dive deeper into any of these statements, or do you have further questions? Here are some related questions you might find interesting:
- What does it mean for a limit to "exist" at a specific point?
- How do we determine if a function is continuous at a point?
- How does an open or closed circle on a graph affect the limit of a function?
- What are some examples of limits that do not exist?
- What is the significance of the behavior of a function near discontinuities?
Tip: When evaluating limits, always check both the left-hand limit () and right-hand limit () separately. The limit exists only if both one-sided limits agree.
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Math Problem Analysis
Mathematical Concepts
Limits
Continuity
Piecewise Functions
Formulas
lim (x → c) f(x)
Theorems
Limit Existence
Continuity Theorem
Suitable Grade Level
Grades 10-12