Math Problem Statement

otkud dobe ovu formulu?

otkud dobe ovu formulu?

Solution

To understand the formula in the image, let's break down the mathematics step-by-step based on your uploaded content:

  1. Expression for Z5Z^5: The formula appears to describe the relationship between a complex number ZZ in polar form and its magnitude and argument.

  2. Polar Representation: Any complex number ZZ can be represented in polar form as: Z=r(cosθ+isinθ)=reiθ,Z = r (\cos \theta + i \sin \theta) = r e^{i\theta}, where rr is the modulus (Z|Z|) and θ\theta is the argument (arg(Z)\arg(Z)).

  3. Equation Given: From the image, Z5=Z(12+i32)Z^5 = Z\left(\frac{1}{2} + i\frac{\sqrt{3}}{2}\right):

    • 12+i32\frac{1}{2} + i\frac{\sqrt{3}}{2} is a known complex number in polar form with r=1r = 1 and argument π3\frac{\pi}{3}.
  4. Key Observation: To satisfy Z5=Z(12+i32)Z^5 = Z \cdot (\frac{1}{2} + i\frac{\sqrt{3}}{2}), the modulus rr of ZZ must be consistent after raising to the 5th power: r5=r.r^5 = r. This leads to the condition that r=1r = 1 (since the modulus of ZZ is normalized for polar rotations).

  5. Verification: The square root term used, 14+34=1=1\sqrt{\frac{1}{4} + \frac{3}{4}} = \sqrt{1} = 1, ensures the modulus normalization.

Why This Formula is Used:

The formula stems from the fact that for complex numbers:

  • Rotations (like multiplying by 12+i32\frac{1}{2} + i\frac{\sqrt{3}}{2}) occur on the unit circle, meaning the modulus rr remains 11 after successive powers.
  • The argument θ\theta of ZZ rotates by multiples of π3\frac{\pi}{3} due to the multiplication factor.

Do you want me to explain in more depth, such as working through the derivation or extending to examples?

Related Questions:

  1. How do you convert a complex number from rectangular to polar form?
  2. What is the geometric interpretation of multiplying complex numbers?
  3. Why does the unit circle play a significant role in these transformations?
  4. How does De Moivre's theorem apply to powers of complex numbers?
  5. What are the practical applications of this formula?

Tip:

Remember, multiplying complex numbers in polar form corresponds to adding their arguments

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Polar Form
De Moivre's Theorem
Modulus and Argument

Formulas

Z = r(cos θ + i sin θ) = r e^(iθ)
Z^5 = Z (1/2 + i√3/2)
r^5 = r

Theorems

De Moivre's Theorem

Suitable Grade Level

Grades 11-12