To find the boundaries for a class interval, you typically adjust the given class limits slightly to include all possible values that belong to the class, considering the precision of the data. The boundaries are determined by subtracting and adding a small value, typically 0.5 of the smallest unit of measurement, to the lower and upper limits, respectively.

Given the class interval 1.87–3.43:

1. Identify the class limits:

   • Lower class limit: 1.87
   • Upper class limit: 3.43

2. Determine the class boundaries:

   • The smallest unit of measurement for these limits is 0.01 (since the values are given to two decimal places).
   • To find the class boundaries, subtract 0.005 from the lower limit and add 0.005 to the upper limit.

3. Calculate the class boundaries: $\text{Lower boundary} = 1.87 - 0.005 = 1.865$ $\text{Upper boundary} = 3.43 + 0.005 = 3.435$

Thus, the class boundaries for the interval 1.87–3.43 are 1.865 to 3.435.

Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:

1. What is the purpose of determining class boundaries in statistics?
2. How would the class boundaries change if the class interval was 4.00–6.50?
3. What is the difference between class limits and class boundaries in frequency distributions?
4. How would you calculate the midpoint of a class interval, and what does it represent?
5. Why do we subtract and add half of the smallest unit when calculating class boundaries?

Tip: Class boundaries are essential in creating histograms and frequency polygons, as they ensure that each class interval includes all possible data points for accurate representation.