Math Problem Statement

The histogram of a frequency distribution of an end-point convention is given below, 14 12 10 8 6 4 2 (a) What are the class boundaries? Use end-point convention. (b) What's the width of the classes? (c) Calculate the Mean and Standard deviation using the frequency distribution table.

Solution

In order to answer these questions, I need more specific data from the frequency distribution (e.g., the class intervals and corresponding frequencies). Since you mentioned a histogram, I'll assume there are class intervals along the horizontal axis, with frequencies on the vertical axis.

Let's break this down step-by-step based on what we can infer:

(a) Class Boundaries (using End-Point Convention):

Class boundaries are the actual limits of the class intervals. If you are using an end-point convention (where class intervals are inclusive of the end-points), the lower class boundary of the first class is the smallest value in the distribution, and the upper class boundary of the last class is the largest value.

Without exact class intervals, I can’t calculate the boundaries precisely, but here’s a general guide:

  • If your class intervals are given as something like 10-20, 21-30, etc., the class boundaries would adjust to remove gaps, so they'd become:
    • Lower Bound: The starting value of the class (e.g., 9.5 for 10-20).
    • Upper Bound: The upper value of the class plus a small amount (e.g., 20.5 for 10-20).

(b) Class Width:

The class width is the difference between the upper and lower boundaries of any given class.

  • Class width formula: Class Width=Upper class boundaryLower class boundary\text{Class Width} = \text{Upper class boundary} - \text{Lower class boundary}

For example, if a class interval is 10-20, then: Class Width=20.59.5=11\text{Class Width} = 20.5 - 9.5 = 11 You can calculate this once the specific class intervals are known.

(c) Mean and Standard Deviation:

To calculate these, we need to create a frequency distribution table with midpoints of each class and their frequencies. Let’s assume you have the data from your histogram (such as class intervals and frequencies). Here's how you'd compute:

  1. Calculate the Mean: Mean(μ)=(fx)f\text{Mean} (\mu) = \frac{\sum (f \cdot x)}{\sum f} where:

    • ff = frequency of the class
    • xx = midpoint of the class
    • f\sum f = sum of frequencies
  2. Calculate the Standard Deviation: Standard Deviation(σ)=f(xμ)2f\text{Standard Deviation} (\sigma) = \sqrt{\frac{\sum f(x - \mu)^2}{\sum f}} where:

    • μ\mu is the mean (from step 1)
    • xx is the class midpoint
    • ff is the class frequency

Next Steps:

Please provide the specific class intervals and frequencies from the histogram, and I can calculate the class boundaries, mean, and standard deviation for you.


Would you like more details on any of these steps, or do you have any questions?

Follow-Up Questions:

  1. What is the exact set of class intervals and frequencies in your histogram?
  2. Are there any gaps between your class intervals?
  3. Do you want me to guide you through calculating midpoints and setting up a frequency distribution table?
  4. Are you familiar with how to adjust for class boundaries in cases where intervals are given?
  5. Do you need a visual guide to understand the computation of standard deviation?

Tip:

When calculating the mean and standard deviation from grouped data, always start by finding the midpoints of the class intervals as they serve as representatives of all the data within each class.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Frequency Distribution
Class Boundaries
Mean
Standard Deviation

Formulas

Class Width = Upper class boundary - Lower class boundary
Mean (μ) = Σ(f * x) / Σf
Standard Deviation (σ) = sqrt[Σf(x - μ)^2 / Σf]

Theorems

Concept of Mean
Standard Deviation Formula

Suitable Grade Level

Grades 10-12