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The problem asks to calculate the uncertainty in the kinetic energy of a bowling ball, given by the equation:

\[
E_k = \frac{1}{2} m v^2
\]

### Known quantities:
- Speed \( v = 12 \, \text{m/s} \)
- Mass \( m = 2.01 \, \text{kg} \)

To calculate the uncertainty in kinetic energy, we use the propagation of uncertainties. The general rule for uncertainty propagation in multiplication or power functions states:

\[
\frac{\Delta E_k}{E_k} = \sqrt{\left( \frac{\Delta m}{m} \right)^2 + \left( 2 \cdot \frac{\Delta v}{v} \right)^2 }
\]

Where:
- \( \Delta E_k \) is the uncertainty in kinetic energy,
- \( \Delta m \) is the uncertainty in mass,
- \( \Delta v \) is the uncertainty in velocity.

Since the problem doesn't explicitly provide the uncertainties in mass and velocity, you would typically assume them based on the precision of the given measurements. Common assumptions for uncertainties:
- For mass \( m = 2.01 \, \text{kg} \), uncertainty might be \( \pm 0.01 \, \text{kg} \),
- For velocity \( v = 12 \, \text{m/s} \), uncertainty might be \( \pm 0.1 \, \text{m/s} \).

Would you like to proceed with these assumptions or provide different uncertainties?

Once clarified, I can compute the kinetic energy and its uncertainty.

Calculate the uncertainty in the kinetic energy of a bowling ball. The equation is Ek = ½ mv² and the following measurements were taken: Speed = 12 ms⁻¹, Mass = 2.01 kg.

Calculate the uncertainty in the kinetic energy of a bowling ball using given speed (12 ms⁻¹) and mass (2.01 kg). Learn about uncertainty propagation in physics and kinetic energy formulas, suitable for high school physics students.

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