To answer the research question, "Is there any difference between domestic students and international students in the average number of practice quizzes attempted?", the correct statistical test to use is a two-sample independent t-test. This is because:

1. Two groups involved: You are comparing two independent groups (domestic students vs. international students).
2. Continuous variable: The number of practice quizzes attempted is a continuous numerical variable.
3. Unknown population standard deviation: Since the population standard deviation is not known, the t-test is more appropriate than a z-test.
4. Testing for differences in means: The goal is to compare the average number of quizzes attempted between the two groups.

Key Assumptions:

• The number of quizzes attempted is normally distributed in each group, or the sample sizes are sufficiently large for the Central Limit Theorem to apply.
• The variances of the two groups are approximately equal (if not, you could use a version of the t-test that does not assume equal variances, such as Welch's t-test).

Would you like more details on how to perform this test, or how to interpret the results?

Here are five related questions to expand your understanding:

1. How do we check if the variances of the two groups are equal?
2. What is Welch's t-test, and when should it be used instead of the regular t-test?
3. How do we interpret the p-value obtained from the two-sample t-test?
4. What role does the Central Limit Theorem play in justifying the use of the t-test?
5. How could non-normality of data affect the results of the t-test?

Tip: Always check assumptions before performing a statistical test, as violations may lead to inaccurate conclusions.