Math Problem Statement

𝑝 and π‘ž are propositions. i. Construct a truth table to show the truth values of ~𝑝 β†’ π‘ž and π‘Λ…π‘ž ii. State, with a reason, if ~𝑝 β†’ π‘ž and π‘Λ…π‘ž are logically equivalent.

Solution

Let's go through the steps to solve this problem.

i. Constructing a truth table for Β¬pβ†’q\neg p \to q and p∨qp \vee q:

We have two propositions, pp and qq, each of which can take the values True (T) or False (F). Let's first define the logical operations involved:

  • Negation (Β¬p\neg p): This is True when pp is False and False when pp is True.
  • Implication (β†’\to): For Β¬pβ†’q\neg p \to q, this is False only when the antecedent (Β¬p\neg p) is True and the consequent (qq) is False. In all other cases, it's True.
  • Disjunction (∨\vee): For p∨qp \vee q, this is True if at least one of pp or qq is True, and False if both are False.

Now, let's construct the truth table.

ppqqΒ¬p\neg pΒ¬pβ†’q\neg p \to qp∨qp \vee q
TTFTT
TFFTT
FTTTT
FFTFF

ii. Determining if Β¬pβ†’q\neg p \to q and p∨qp \vee q are logically equivalent:

Two propositions are logically equivalent if they have the same truth values for all possible truth values of pp and qq.

From the truth table, we can observe that the truth values of Β¬pβ†’q\neg p \to q and p∨qp \vee q are the same for all combinations of pp and qq. Therefore, we conclude that:

Β¬pβ†’qis logically equivalent top∨q\neg p \to q \quad \text{is logically equivalent to} \quad p \vee q

Reason: Both propositions result in the same truth values for all possible combinations of truth values of pp and qq, which confirms their logical equivalence.


Would you like further details on any part of the explanation or have any questions?

Here are 5 related questions to deepen your understanding:

  1. How would the truth table look for the proposition p→qp \to q?
  2. What is the truth value of p∨qp \vee q when both pp and qq are False?
  3. Can two propositions be logically equivalent if their truth values differ in only one case?
  4. How does the truth table for ¬(p∧q)\neg (p \wedge q) compare to that of p∨qp \vee q?
  5. What logical law can be used to justify the equivalence of Β¬pβ†’q\neg p \to q and p∨qp \vee q?

Tip: When constructing truth tables, it's helpful to break complex expressions into smaller parts, evaluating each step independently before combining results.

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Math Problem Analysis

Mathematical Concepts

Logic
Propositional Logic
Truth Tables
Logical Equivalence

Formulas

Negation (~p)
Implication (~p β†’ q)
Disjunction (pΛ…q)

Theorems

Logical Equivalence Theorem

Suitable Grade Level

Grades 9-12