Math Problem Statement

Create a truth table for (~p→q)˄p→~q

Solution

To create a truth table for the logical expression (pq)pq(\sim p \to q) \land p \to \sim q, we'll break it down step by step.

Expression:

(pq)pq(\sim p \to q) \land p \to \sim q

This is a conditional statement where:

  • p\sim p means "not p."
  • pqp \to q means "if p then q" (implication).
  • \land means "and."
  • The main conditional is the outer \to.

Steps for the Truth Table:

  1. Calculate p\sim p (negation of pp).
  2. Calculate pq\sim p \to q (implication).
  3. Calculate (pq)p(\sim p \to q) \land p (conjunction).
  4. Calculate q\sim q (negation of qq).
  5. Finally, calculate (pq)pq(\sim p \to q) \land p \to \sim q (implication).
ppqqp\sim ppq\sim p \to q(pq)p(\sim p \to q) \land pq\sim q(pq)pq(\sim p \to q) \land p \to \sim q
TTFTTFF
TFFFFTT
FTTTFFT
FFTFFTT

Explanation:

  • The third column is p\sim p, the negation of pp.
  • The fourth column is the implication pq\sim p \to q.
  • The fifth column is the conjunction (pq)p(\sim p \to q) \land p.
  • The sixth column is q\sim q, the negation of qq.
  • The final column is the implication (pq)pq(\sim p \to q) \land p \to \sim q, which gives us the truth value of the overall expression.

Would you like any clarifications on these steps?


Relative Questions:

  1. How do you evaluate implications in a truth table?
  2. Why does the conjunction (pq)p(\sim p \to q) \land p affect the overall truth value?
  3. What are common logical equivalences related to implications?
  4. How can you use truth tables to determine tautologies or contradictions?
  5. How does negating the whole statement affect the truth table?

Tip: When working with implications, remember that pqp \to q is false only when pp is true and qq is false.

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Math Problem Analysis

Mathematical Concepts

Propositional Logic
Truth Tables
Logical Implication
Logical Negation

Formulas

Implication: p → q
Negation: ~p
Conjunction: p ∧ q

Theorems

Truth Table Analysis
Implication in Logic

Suitable Grade Level

Grades 9-12 (Advanced Logic)