Math Problem Statement

Complete the truth table for F(x, y, z) = x + yz

Solution

The truth table you've provided is for the Boolean expression F(x,y,z)=x+yzF(x, y, z) = x + yz. Let's complete the truth table based on this expression.

Boolean Expression Breakdown:

  • F(x,y,z)=x+yzF(x, y, z) = x + yz
  • x+yzx + yz means that the output is true if either xx is true or both yy and zz are true.

We will calculate the result for each combination of xx, yy, and zz.

xxyyzzx+yzx + yz
1111
1101
1011
1001
0111
0100
0010
0000

Explanation:

  • For the first four rows, x=1x = 1, which directly makes F=1F = 1 (since x+yz=1x + yz = 1).
  • For the fifth row, x=0x = 0, but y=1y = 1 and z=1z = 1, so yz=1yz = 1, making F=1F = 1.
  • For the sixth row, x=0x = 0, y=1y = 1, but z=0z = 0, so yz=0yz = 0, making F=0F = 0.
  • For the last two rows, x=0x = 0, and either y=0y = 0 or z=0z = 0, making yz=0yz = 0, so F=0F = 0.

Do you want further clarification on any steps? Here are five follow-up questions:

  1. How would you represent the Boolean expression x+yzx + yz using logic gates?
  2. What would the Karnaugh map look like for this Boolean function?
  3. How would the result change if we modified the expression to xyzx \cdot yz?
  4. What is the dual of the Boolean function x+yzx + yz?
  5. How can this truth table be simplified using Boolean algebra?

Tip: When dealing with truth tables, check each row step by step by focusing on how individual variables affect the overall output!

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Math Problem Analysis

Mathematical Concepts

Boolean Algebra
Logic Gates
Truth Tables

Formulas

F(x, y, z) = x + yz

Theorems

Distributive property of Boolean algebra

Suitable Grade Level

Grades 9-12