To draw the combinational circuit that directly implements the Boolean expression $F(x, y, z) = xyz + (y' + z)$, we break it down into basic logic gates.

Step-by-step procedure:

1. AND gate:

   • The first term is $xyz$, which represents an AND operation between $x$, $y$, and $z$. Use a 3-input AND gate for this.

2. NOT gate:

   • The second part of the expression involves $y'$, which is the negation of $y$. Use a NOT gate to invert $y$.

3. OR gate:

   • After negating $y$, we add it to $z$ using an OR gate to implement $y' + z$.

4. Final OR gate:

   • Now, the result of the AND gate $xyz$ and the OR gate $y' + z$ are added together using another OR gate, giving the final output $F(x, y, z)$.

Circuit structure:

• Input: $x$, $y$, and $z$
• 1st AND Gate: Inputs $x$, $y$, and $z$, output = $xyz$
• NOT Gate: Input $y$, output = $y'$
• 1st OR Gate: Inputs $y'$ and $z$, output = $y' + z$
• 2nd OR Gate: Inputs $xyz$ and $y' + z$, output = $F(x, y, z)$

Visualizing the circuit:

1. Draw three input lines labeled $x$, $y$, and $z$.
2. Connect $x$, $y$, and $z$ to a 3-input AND gate.
3. Place a NOT gate on $y$'s line to produce $y'$.
4. Connect $y'$ and $z$ to a 2-input OR gate.
5. Finally, use a 2-input OR gate to combine the output of the AND gate $xyz$ and the OR gate $y' + z$ to produce $F(x, y, z)$.

Would you like a detailed diagram for this? Let me know if you have any questions!

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Here are five related questions:

1. How do you optimize Boolean expressions using Boolean algebra?
2. What are the differences between combinational and sequential circuits?
3. How would this circuit change if the Boolean expression involved XOR gates?
4. Can you implement this circuit using only NAND gates?
5. How do Karnaugh maps help in simplifying Boolean expressions?

Tip: When working with Boolean expressions, always simplify them first using Boolean algebra or Karnaugh maps to reduce the number of gates needed!