Math Problem Statement

  1. For all x in real number,thetr exist a y in real number such that x<y 2. There exist a x in real number such that for all y in real number, x<y True or False

Solution

Let's break down the two statements one by one:

  1. For all xx in real numbers, there exists a yy in real numbers such that x<yx < y:

    This statement is True. For any real number xx, you can always find another real number yy that is greater than xx. For example, if x=100x = 100, you can choose y=101y = 101 or y=1000y = 1000, etc. Since the real numbers are unbounded above, there is always a yy such that x<yx < y.

  2. There exists an xx in real numbers such that for all yy in real numbers, x<yx < y:

    This statement is False. There is no real number xx that is less than all other real numbers because the real numbers are unbounded below. For any xx, you can always find a smaller yy. Therefore, no single xx can satisfy the condition of being less than all yy.

Summary:

  1. True.
  2. False.

Would you like further explanation or details?

Here are some related questions:

  1. What is the difference between bounded and unbounded sets?
  2. Can you explain the concept of real numbers being unbounded?
  3. Is there a largest or smallest real number?
  4. What happens in similar conditions for rational or irrational numbers?
  5. How does the concept of infinity relate to real numbers?

Tip: Understanding how real numbers are unbounded both above and below is essential in many mathematical fields, especially calculus and analysis.

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Math Problem Analysis

Mathematical Concepts

Real Numbers
Unbounded Sets
Inequalities

Formulas

-

Theorems

Real numbers are unbounded above and below

Suitable Grade Level

Grades 10-12