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The problem states that the total cost, $ C(x) $, for renting a truck is defined by the function:

\[
C(x) = 0.20x + 9.25
\]

where:
- $ x $ is the number of miles driven,
- $ 0.20x $ represents the additional cost per mile driven (20 cents per mile),
- $ 9.25 $ is the base fee (in dollars).

We are tasked with finding the total cost if Donna drove 30 miles. Substituting $ x = 30 $ into the equation:

\[
C(30) = 0.20(30) + 9.25
\]

1. Multiply $ 0.20 \times 30 $:
   \[
   0.20 \times 30 = 6.00
   \]

2. Add the base fee of $ 9.25 $:
   \[
   C(30) = 6.00 + 9.25 = 15.25
   \]

Thus, the total rental cost is:

\[
\boxed{15.25 \, \text{dollars}}
\]

---

Would you like a more detailed breakdown or explanation of any steps?

### Related Questions:
1. What would the total cost be if Donna drove 50 miles instead of 30?
2. How would the formula change if the cost per mile increased to 25 cents?
3. What is the base fee percentage of the total cost if Donna drove 100 miles?
4. Can you express the function $ C(x) $ in terms of cents instead of dollars?
5. If Donna's budget was $20, how many miles could she afford to drive?

### Tip:
When solving cost-related problems, always check if all components (base fee, variable rate, etc.) are accounted for in the equation.

Donna rented a truck for one day. There was a base fee of $9.25, and there was an additional charge of 20 cents for each mile driven. The total cost, C(x) (in dollars), for driving x miles is given by the following function: C(x) = 0.20x + 9.25. What is the total rental cost if Donna drove 30 miles?

Find out the total truck rental cost for driving 30 miles, using the function C(x) = 0.20x + 9.25. This problem includes concepts of linear equations and arithmetic, suitable for Grades 6-8.

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