Charlie rented a truck for one day. There was a base fee of $19.95 , and there was an additional charge of 90 cents for each mile driven. Charlie had to pay $155.85 when he returned the truck. For how many miles did he drive the truck?
 


To solve for the number of miles Charlie drove, we can set up an equation based on the information provided:

1. The base fee is $ \$19.95 $.
2. The additional charge is $ \$0.90 $ per mile.
3. The total amount Charlie paid is $ \$155.85 $.

Let $ x $ represent the number of miles Charlie drove. The total cost can be expressed as:

\[
\text{Total cost} = \text{Base fee} + (\text{Charge per mile} \times \text{Miles driven})
\]

Substitute the known values into the equation:

\[
155.85 = 19.95 + 0.90x
\]

Now, solve for $ x $:

1. Subtract 19.95 from both sides:

\[
155.85 - 19.95 = 0.90x
\]

\[
135.90 = 0.90x
\]

2. Divide both sides by 0.90 to isolate $ x $:

\[
x = \frac{135.90}{0.90}
\]

\[
x = 151
\]

Thus, Charlie drove **151 miles**.

Would you like further details or have any questions?

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Here are 5 related questions to expand your understanding:
1. What would the total cost be if Charlie drove 200 miles?
2. How would the equation change if the base fee increased by $5?
3. What is the cost per mile if Charlie had to pay a total of $200?
4. How many miles would Charlie have driven if he paid $100 instead?
5. How much would Charlie pay if the cost per mile was reduced to $0.80?

**Tip**: Always isolate the variable by performing inverse operations step by step!

Charlie rented a truck for one day. There was a base fee of $19.95, and there was an additional charge of 90 cents for each mile driven. Charlie had to pay $155.85 when he returned the truck. For how many miles did he drive the truck?

Learn how to calculate the number of miles driven in a truck rental scenario, where the base fee is $19.95 and the cost per mile is $0.90. Charlie paid a total of $155.85. This problem uses linear equations and is suitable for students in Grades 6-8.

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