Math Problem Statement

The value of sec 135° is _______ because 135° is in quadrant ______. The reference angle is ______ and the exact value of sec 135° is ______.

Solution

The question on your screen is asking about the secant function for an angle of 135135^\circ. Let's break it down step by step:

  1. Quadrant for 135135^\circ:

    • 135135^\circ is in the second quadrant because angles between 9090^\circ and 180180^\circ lie in this quadrant.
  2. Reference angle:

    • The reference angle for an angle in the second quadrant is calculated as 180θ180^\circ - \theta.
    • For θ=135\theta = 135^\circ, the reference angle is: 180135=45180^\circ - 135^\circ = 45^\circ
  3. Secant in the second quadrant:

    • Secant (secθ\sec \theta) is the reciprocal of the cosine (cosθ\cos \theta).
    • In the second quadrant, cosine is negative, so the secant will also be negative.
  4. Exact value of sec135\sec 135^\circ:

    • The reference angle is 4545^\circ, and cos45=12\cos 45^\circ = \frac{1}{\sqrt{2}}.
    • Therefore, sec45=2\sec 45^\circ = \sqrt{2}, and since 135135^\circ is in the second quadrant, sec135=2\sec 135^\circ = -\sqrt{2}.

Correct Choices:

  • Quadrant: Second quadrant.
  • Reference Angle: 4545^\circ.
  • Exact Value: 2-\sqrt{2}.

Do you need more details or further clarification?


Here are 5 related questions to enhance your understanding:

  1. What is the secant function in terms of sine and cosine?
  2. How do you find the reference angle for any given angle?
  3. Why is the cosine negative in the second quadrant?
  4. Can you explain how to compute secant for angles in different quadrants?
  5. What is the relationship between secant and cosecant?

Tip: To easily find the reference angle, always compare the given angle to the nearest x-axis boundary (0°, 180°, or 360°).

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Secant Function
Reference Angle
Quadrants

Formulas

sec(θ) = 1 / cos(θ)
Reference angle for second quadrant: 180° - θ

Theorems

Trigonometric functions in different quadrants

Suitable Grade Level

Grades 10-12