Math Problem Statement

Find a possible formula for the trigonometric function whose values are in the following table: x: 0, 4, 8, 12, 16, 20, 24 y: -6, -4, -2, -4, -6, -4, -2

Solution

We are given a table of values for a trigonometric function and are asked to find a possible formula for the function.

The values of xx are: 0,4,8,12,16,20,240, 4, 8, 12, 16, 20, 24

The corresponding values of yy are: 6,4,2,4,6,4,2-6, -4, -2, -4, -6, -4, -2

Step 1: Identify the periodic behavior

The values of yy repeat in a pattern, suggesting the function is periodic. A possible candidate for such behavior is the cosine or sine function, as they naturally exhibit oscillatory behavior. The pattern seems to repeat every 16 units (from x=0x = 0 to x=16x = 16).

Thus, the period TT of the function could be 16.

Step 2: Amplitude and vertical shift

The maximum value of yy is 2-2, and the minimum value is 6-6. The amplitude AA can be calculated as: A=maxmin2=2(6)2=2A = \frac{\text{max} - \text{min}}{2} = \frac{-2 - (-6)}{2} = 2

The midline (vertical shift) is the average of the maximum and minimum values: D=max+min2=2+(6)2=4D = \frac{\text{max} + \text{min}}{2} = \frac{-2 + (-6)}{2} = -4

So, the function has an amplitude of 2 and is vertically shifted down by 4 units.

Step 3: Determine the trigonometric form

We suspect the function is either a cosine or sine function. The yy-values start at a minimum at x=0x = 0, which is characteristic of a cosine function with a phase shift.

The general form for the cosine function is: y=Acos(Bx+C)+Dy = A \cos(Bx + C) + D Where:

  • AA is the amplitude (2),
  • BB is related to the period TT by B=2πTB = \frac{2\pi}{T},
  • CC is the phase shift,
  • DD is the vertical shift (-4).

Since the period T=16T = 16, we have: B=2π16=π8B = \frac{2\pi}{16} = \frac{\pi}{8}

Step 4: Phase shift

The cosine function normally starts at its maximum when x=0x = 0, but here the function starts at its minimum. To adjust for this, we need a phase shift of π\pi (which moves it to its minimum at x=0x = 0).

Thus, the phase shift C=πC = \pi.

Step 5: Final function

The possible formula for the trigonometric function is: y=2cos(π8x+π)4y = 2 \cos\left(\frac{\pi}{8}x + \pi\right) - 4

Would you like further clarification or have any questions?


Here are five related questions:

  1. How would the formula change if the phase shift was different?
  2. What if the function was a sine function instead of cosine?
  3. Can you derive the formula using sine instead of cosine?
  4. How do you determine the period of a trigonometric function from data points?
  5. How can we verify the correctness of this function?

Tip: When working with periodic functions, always examine the amplitude, period, phase shift, and vertical shift carefully. They define the behavior of the trigonometric function.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Periodic Functions
Cosine Function
Amplitude
Phase Shift
Period

Formulas

y = A * cos(Bx + C) + D
Amplitude: A = (max - min) / 2
Vertical shift (midline): D = (max + min) / 2
B = 2π / T, where T is the period

Theorems

Properties of periodic trigonometric functions

Suitable Grade Level

Grades 10-12