Math Problem Statement

The figure shows the graph of a trigonometric function f. Which of the following could be an expression for f(x)?

Solution

To solve this problem, we need to identify the equation of the given trigonometric function f(x)f(x) by analyzing its amplitude, frequency, phase shift, and vertical shift.

Step-by-step Analysis:

  1. Amplitude: The amplitude is the distance from the midline of the graph to its maximum or minimum. In this case, the maximum value is 33 and the minimum value is 5-5. The amplitude is half the range: Amplitude=maxmin2=3(5)2=4\text{Amplitude} = \frac{\text{max} - \text{min}}{2} = \frac{3 - (-5)}{2} = 4 However, the vertical shift affects the observed amplitude.

  2. Vertical Shift: The vertical shift is the midline of the graph. The midline is calculated as: Midline=max+min2=3+(5)2=1\text{Midline} = \frac{\text{max} + \text{min}}{2} = \frac{3 + (-5)}{2} = -1 Thus, the graph is shifted down by 1 unit.

  3. Period: The period of the function is determined by the distance it takes for the wave to repeat. From the graph, one full cycle occurs from x=0x = 0 to x=πx = \pi. Thus, the period is: Period=π\text{Period} = \pi The formula for the period of a sine or cosine function is: Period=2πB\text{Period} = \frac{2\pi}{B} Solving for BB: B=2πPeriod=2ππ=2B = \frac{2\pi}{\text{Period}} = \frac{2\pi}{\pi} = 2

  4. Phase Shift: The graph appears to be shifted horizontally. To determine the phase shift, note that the graph reaches its maximum at x=π4x = \frac{\pi}{4}. This corresponds to the phase shift: Phase Shift=π4\text{Phase Shift} = \frac{\pi}{4}

  5. Choice of Function: From the shape of the graph, it resembles a cosine wave. The cosine function has its maximum at x=0x = 0 before shifting. Considering the phase shift, vertical shift, and amplitude, the function takes the form: f(x)=3cos(2(xπ4))1f(x) = 3\cos\left(2\left(x - \frac{\pi}{4}\right)\right) - 1

Thus, the correct answer is: (A) 3cos(2(xπ4))1\boxed{(A) \ 3\cos\left(2\left(x - \frac{\pi}{4}\right)\right) - 1}


Do you want further clarification or details about any step?

Related Questions:

  1. How do we determine if the function is sine or cosine-based?
  2. Why does the vertical shift affect the midline of the graph?
  3. Can the phase shift be calculated differently if using a sine function?
  4. How do we generalize the formula for sinusoidal functions?
  5. Why does the amplitude remain positive, regardless of the graph's orientation?

Tip:

When analyzing trigonometric graphs, always check amplitude, vertical shift, period, and phase shift systematically to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Graphing Trigonometric Functions

Formulas

Amplitude = (max - min) / 2
Vertical shift = (max + min) / 2
Period = 2π / B
Phase shift = horizontal shift of the function

Theorems

Properties of sine and cosine functions
Periodicity of trigonometric functions

Suitable Grade Level

Grades 10-12