(sin(𝜋/3)(tan𝜋/6) + csc(𝜋/4)^2
 


Let's solve the expression:

\[
\sin\left(\frac{\pi}{3}\right) \cdot \tan\left(\frac{\pi}{6}\right) + \csc^2\left(\frac{\pi}{4}\right)
\]

### Step 1: Calculate each trigonometric function
- \(\sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2}\)
- \(\tan\left(\frac{\pi}{6}\right) = \frac{1}{\sqrt{3}}\)
- \(\csc\left(\frac{\pi}{4}\right) = \frac{1}{\sin\left(\frac{\pi}{4}\right)} = \frac{1}{\frac{\sqrt{2}}{2}} = \sqrt{2}\)
- \(\csc^2\left(\frac{\pi}{4}\right) = \left(\sqrt{2}\right)^2 = 2\)

### Step 2: Substitute and simplify
The expression becomes:
\[
\sin\left(\frac{\pi}{3}\right) \cdot \tan\left(\frac{\pi}{6}\right) + \csc^2\left(\frac{\pi}{4}\right)
\]
Substitute the values:
\[
\frac{\sqrt{3}}{2} \cdot \frac{1}{\sqrt{3}} + 2
\]

Simplifying the first term:
\[
\frac{\sqrt{3}}{2} \cdot \frac{1}{\sqrt{3}} = \frac{1}{2}
\]

Now, add the second term:
\[
\frac{1}{2} + 2 = \frac{1}{2} + \frac{4}{2} = \frac{5}{2}
\]

### Final Answer:
\[
\boxed{\frac{5}{2}}
\]

Would you like any additional details on this solution?

Here are 5 related questions you might find helpful:
1. What is the general formula for trigonometric identities involving sine and tangent?
2. How does the csc function relate to sine in trigonometry?
3. How do you find the values of trigonometric functions at standard angles?
4. What is the significance of \(\pi\)-related angles in the unit circle?
5. How do you simplify trigonometric expressions involving multiple functions?

**Tip:** Memorizing the exact values of trigonometric functions for common angles like \(\frac{\pi}{6}\), \(\frac{\pi}{4}\), and \(\frac{\pi}{3}\) can help speed up calculations!

Understand how to solve the trigonometric expression sin(π/3)tan(π/6) + csc(π/4)^2 with step-by-step instructions. This problem involves fundamental trigonometric functions and their identities, suitable for students in Grades 10-12.

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