Math Problem Statement

Suppose you are going to estimate

I=∫40cos3xdx.

using the trapezoidal rule.

According to the error bound, what is the minimum number of points nmin needed to guarantee that the absolute value of the error is less than 10−7 ?

Solution

To estimate the integral

I=04cos(3x)dxI = \int_0^4 \cos(3x)\, dx

using the trapezoidal rule, we need to determine the minimum number of points nminn_{\text{min}} such that the error bound is less than 10710^{-7}.

Error Bound for the Trapezoidal Rule:

The error bound for the trapezoidal rule is given by:

ET(ba)312n2maxaxbf(x)E_T \leq \frac{(b - a)^3}{12n^2} \max_{a \leq x \leq b} \left| f''(x) \right|

where:

  • a=0a = 0, b=4b = 4 (the limits of integration),
  • f(x)=cos(3x)f(x) = \cos(3x),
  • f(x)f''(x) is the second derivative of f(x)f(x),
  • nn is the number of intervals (or points), and
  • ETE_T is the error.

Step 1: Find f(x)f''(x)

We start by finding the second derivative of f(x)=cos(3x)f(x) = \cos(3x):

  • First derivative: f(x)=3sin(3x)f'(x) = -3\sin(3x),
  • Second derivative: f(x)=9cos(3x)f''(x) = -9\cos(3x).

The maximum value of f(x)|f''(x)| is 99, since the cosine function ranges between 1-1 and 11.

Step 2: Set up the error bound formula

Now, we substitute the values into the error bound formula:

ET(40)312n29=6412n29=48n2E_T \leq \frac{(4 - 0)^3}{12n^2} \cdot 9 = \frac{64}{12n^2} \cdot 9 = \frac{48}{n^2}

Step 3: Solve for nn

We want the error ETE_T to be less than 10710^{-7}, so:

48n2107\frac{48}{n^2} \leq 10^{-7}

Solving for n2n^2:

n248107=4.8×108n^2 \geq \frac{48}{10^{-7}} = 4.8 \times 10^8

Taking the square root:

n4.8×10821909.6n \geq \sqrt{4.8 \times 10^8} \approx 21909.6

Thus, the minimum number of points nminn_{\text{min}} required is nmin21910n_{\text{min}} \approx 21910.

Final Answer:

The minimum number of points nminn_{\text{min}} needed to guarantee that the absolute value of the error is less than 10710^{-7} is approximately 21,910.

Would you like to go over the details, or do you have any other questions?


Here are five related questions:

  1. How does the trapezoidal rule compare with Simpson's rule in terms of error?
  2. What is the error bound formula for Simpson's rule?
  3. How would increasing the number of points impact the accuracy of the trapezoidal rule?
  4. How do numerical integration methods like the trapezoidal rule handle oscillatory functions like cos(3x)\cos(3x)?
  5. Could a different quadrature method provide a more efficient result for this integral?

Tip: Always check the second derivative when estimating errors in numerical integration since it plays a key role in the accuracy of the result.

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Math Problem Analysis

Mathematical Concepts

Numerical Integration
Trapezoidal Rule
Error Bound

Formulas

Trapezoidal Rule Error Bound: E_T ≤ (b - a)^3 / 12n^2 * max|f''(x)|
Second derivative of cos(3x): f''(x) = -9cos(3x)

Theorems

Error Bound Theorem for Numerical Integration

Suitable Grade Level

University Level - Numerical Analysis