Math Problem Statement

Estimate ∫[0 to 1] 12 cos(x^2) dx using the Trapezoidal Rule and the Midpoint Rule, each with n = 4. From a graph of the integrand, decide whether your answers are underestimates or overestimates. What can you conclude about the true value of the integral?

Solution

We are tasked with estimating the integral 0112cos(x2)dx\int_0^1 12 \cos(x^2) \, dx using the Trapezoidal Rule and the Midpoint Rule with n=4n = 4.

Step 1: Subdivide the Interval

The interval [0,1][0, 1] is divided into n=4n = 4 subintervals, so the width of each subinterval is: Δx=104=0.25\Delta x = \frac{1 - 0}{4} = 0.25

The points where we will evaluate the function are:

  • Trapezoidal Rule: x0=0x_0 = 0, x1=0.25x_1 = 0.25, x2=0.5x_2 = 0.5, x3=0.75x_3 = 0.75, x4=1x_4 = 1
  • Midpoint Rule: The midpoints of the intervals: xmid,1=0.125x_{mid,1} = 0.125, xmid,2=0.375x_{mid,2} = 0.375, xmid,3=0.625x_{mid,3} = 0.625, xmid,4=0.875x_{mid,4} = 0.875

Step 2: Apply Trapezoidal Rule

The Trapezoidal Rule formula is: T=Δx2[f(x0)+2f(x1)+2f(x2)+2f(x3)+f(x4)]T = \frac{\Delta x}{2} \left[ f(x_0) + 2f(x_1) + 2f(x_2) + 2f(x_3) + f(x_4) \right] where f(x)=12cos(x2)f(x) = 12 \cos(x^2).

Step 3: Apply Midpoint Rule

The Midpoint Rule formula is: M=Δx[f(xmid,1)+f(xmid,2)+f(xmid,3)+f(xmid,4)]M = \Delta x \left[ f(x_{mid,1}) + f(x_{mid,2}) + f(x_{mid,3}) + f(x_{mid,4}) \right]

Step 4: Numerical Computations

I will now calculate these values numerically. Let me compute them.The numerical estimates for the integral 0112cos(x2)dx\int_0^1 12 \cos(x^2) \, dx using n=4n = 4 are as follows:

  • Trapezoidal Rule Estimate: T10.749T \approx 10.749
  • Midpoint Rule Estimate: M10.907M \approx 10.907

Step 5: Analyze Overestimate or Underestimate

From the graph of the function 12cos(x2)12 \cos(x^2), we observe that the function is concave down on the interval [0,1][0, 1] because its second derivative d2dx2(12cos(x2))\frac{d^2}{dx^2}(12 \cos(x^2)) is negative in this region. This means:

  • The Trapezoidal Rule tends to underestimate the integral because it under-approximates areas under concave down curves.
  • The Midpoint Rule tends to overestimate the integral because it over-approximates the area for concave down curves.

Conclusion:

Since the Trapezoidal Rule provides an underestimate and the Midpoint Rule provides an overestimate, the true value of the integral lies between these two estimates. Therefore, we can conclude: 10.749<0112cos(x2)dx<10.90710.749 < \int_0^1 12 \cos(x^2) \, dx < 10.907

Would you like more details on any part of the calculation?

Here are 5 related questions you might find useful:

  1. How do you compute the error bounds for the Trapezoidal Rule and Midpoint Rule?
  2. How would increasing nn affect the accuracy of these estimates?
  3. Can Simpson’s Rule be applied to this problem for a more accurate estimate?
  4. What is the exact value of this integral, and how does it compare with these estimates?
  5. How does the concavity of a function affect the accuracy of different numerical integration methods?

Tip: Always graph the function before applying numerical integration techniques to better understand the behavior of the curve and the expected accuracy of the methods.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Numerical Integration
Trapezoidal Rule
Midpoint Rule
Concavity
Definite Integrals

Formulas

Trapezoidal Rule: T = (Δx / 2) * [f(x0) + 2*f(x1) + ... + 2*f(x_(n-1)) + f(x_n)]
Midpoint Rule: M = Δx * [f(x_mid1) + f(x_mid2) + ... + f(x_midn)]

Theorems

Concavity Theorem: The concavity of a function affects whether numerical methods give overestimates or underestimates

Suitable Grade Level

Undergraduate Calculus or AP Calculus (Grades 11-12)