Math Problem Statement

System A

System B

System C

{ 2x+4y=-10 [A1]

{2x

2x+4y=-10 [81] 2x+4y=-10 [C1]

-6x-5y=9 [A2] 7y=-21 [B2]

y=-3

[C2]

Answer the questions below.

For each, choose the transformation and then fill in the blank with the correct number. The arrow (→) means the expression on the left becomes the expression on the right.

(a) How do we transform System A into System B?

x Equation [A1] Equation [B1]

Equation [A2] Equation (82)

OxEquation (A1] + Equation [A2] Equation (82)

x Equation [A2] Equation [A1] Equation [B1]

(b) How do we transform System B into System C7

x Equation [81] Equation (C1)

Equation [82] Equation [C2]

Equation [B1] + Equation (82) Equation [C2]

x Equation [82] + Equation [B1] Equation [C1]

Solution

Let's break this down step by step for both (a) and (b).

(a) How do we transform System A into System B?

From the systems given:

  • System A: Equation [A1]:2x+4y=10\text{Equation [A1]}: 2x + 4y = -10 Equation [A2]:6x5y=9\text{Equation [A2]}: -6x - 5y = 9

  • System B: Equation [B1]:2x+4y=10\text{Equation [B1]}: 2x + 4y = -10 Equation [B2]:7y=21\text{Equation [B2]}: 7y = -21

To transform System A into System B, notice that:

  • Equation [A1] is identical to Equation [B1].
  • We need to change Equation [A2] into Equation [B2]. If we solve Equation [A2] for yy, we get: 6x5y=9y=3-6x - 5y = 9 \quad \Rightarrow \quad y = -3 This is equivalent to Equation [B2] because 7y=217y = -21 simplifies to y=3y = -3.

So, to transform System A into System B, Equation [A1] stays the same, and Equation [A2] is transformed into Equation [B2].

Thus, the correct transformation is: [ \boxed{\text{Equation [A1] + Equation [A2] → Equation [B1] + Equation [B2]}} ]

(b) How do we transform System B into System C?

From the systems given:

  • System B: Equation [B1]:2x+4y=10\text{Equation [B1]}: 2x + 4y = -10 Equation [B2]:7y=21\text{Equation [B2]}: 7y = -21

  • System C: Equation [C1]:2x+4y=10\text{Equation [C1]}: 2x + 4y = -10 Equation [C2]:y=3\text{Equation [C2]}: y = -3

To transform System B into System C, notice:

  • Equation [B1] is identical to Equation [C1].
  • Equation [B2] can be solved for yy: 7y=21y=37y = -21 \quad \Rightarrow \quad y = -3 This is Equation [C2].

So, to transform System B into System C, Equation [B1] stays the same, and Equation [B2] transforms into Equation [C2].

Thus, the correct transformation is: [ \boxed{\text{Equation [B1] + Equation [B2] → Equation [C1] + Equation [C2]}} ]


Summary of Answers:

  • (a) System A to System B: Equation [A1] + Equation [A2] → Equation [B1] + Equation [B2]
  • (b) System B to System C: Equation [B1] + Equation [B2] → Equation [C1] + Equation [C2]

Would you like to go over any details or ask any further questions on this?


Here are some related questions you might find useful:

  1. How can we use substitution to solve a system of equations?
  2. What’s the difference between a system of linear equations and a system of nonlinear equations?
  3. How do you solve a system of equations using the elimination method?
  4. What is the graphical interpretation of solving a system of linear equations?
  5. Can we transform a system of equations by multiplying the equations by constants?

Tip: When solving systems of equations, always check if one of the equations is already in a simplified form (like y=3y = -3), which can save you time in solving the system.

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Math Problem Analysis

Mathematical Concepts

Systems of Equations
Algebra
Linear Equations

Formulas

2x + 4y = -10
-6x - 5y = 9
7y = -21
y = -3

Theorems

Solving Systems of Equations by Substitution

Suitable Grade Level

Grades 8-10