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In this image, we are presented with two systems of equations: **System A** and **System B**. System A has the following equations:

1. \( 7x + 4y = -4 \)
2. \( 5x + 8y = 28 \)

System B has the first equation identical to System A:

1. \( 7x + 4y = -4 \)

We need to find the second equation for **System B** that would make both systems equivalent. The options are:

1. \( -14x - 8y = -8 \)
2. \( 12x + 12y = 24 \)
3. \( -14x - 8y = 8 \)
4. \( -12x - 12y = 24 \)

### Solution Approach:

We start by multiplying or manipulating the second equation from **System A** to match one of the given options for **System B**.

The second equation in **System A** is:
\[
5x + 8y = 28
\]

To make it equivalent to one of the given options, we could multiply the whole equation by a constant.

Now, let's multiply the equation by \( -2 \):
\[
-2(5x + 8y) = -2(28)
\]
\[
-10x - 16y = -56
\]
This does not match any of the options provided.

Instead, let’s test multiplying the equation by a different factor, or let’s inspect the options directly and reverse-engineer them.

- The equation \( -14x - 8y = -8 \) can be tested.

But it seems this needs more direct checking.

Do you want

Which of the following terms will make the systems equivalent? System A: 7x + 4y = -4, 5x + 8y = 28. System B: 7x + 4y = -4, ?

Find the equation that makes System A and System B equivalent. This algebraic problem involves solving systems of linear equations, suitable for students in Grades 8-10. Detailed explanation of the substitution and elimination methods.

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