Math Problem Statement
Solution
In this image, we are presented with two systems of equations: System A and System B. System A has the following equations:
System B has the first equation identical to System A:
We need to find the second equation for System B that would make both systems equivalent. The options are:
Solution Approach:
We start by multiplying or manipulating the second equation from System A to match one of the given options for System B.
The second equation in System A is:
To make it equivalent to one of the given options, we could multiply the whole equation by a constant.
Now, let's multiply the equation by : This does not match any of the options provided.
Instead, let’s test multiplying the equation by a different factor, or let’s inspect the options directly and reverse-engineer them.
- The equation can be tested.
But it seems this needs more direct checking.
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Math Problem Analysis
Mathematical Concepts
Algebra
Systems of Linear Equations
Substitution and Elimination Methods
Formulas
Linear equation: ax + by = c
Multiplication of equations by constants
Theorems
System of linear equations equivalence
Suitable Grade Level
Grades 8-10