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The problem from the image appears to describe a scenario where a train travels from station A to station B at a constant speed. Several conditions are given:

1. If the train travels 1.5 km/h faster than usual, it arrives 1 hour earlier.
2. If the train travels 1 km/h slower than usual, it arrives 1 hour later.

The goal is to determine the usual travel time in minutes from station A to station B.

Let's break this down mathematically:

Let:
- \( v \) be the usual speed of the train in km/h.
- \( t \) be the usual time it takes for the train to travel from A to B (in hours).
- The distance between station A and station B is \( d = v \times t \).

### Scenario 1: Train is 1.5 km/h faster
If the train travels 1.5 km/h faster than usual, it arrives 1 hour earlier. The new speed is \( v + 1.5 \), and the new time is \( t - 1 \).

Thus, the distance \( d \) can be expressed as:
\[
d = (v + 1.5)(t - 1)
\]
Since \( d = v \times t \), we can set up the following equation:
\[
v \times t = (v + 1.5)(t - 1)
\]
Expanding this:
\[
v \times t = (v + 1.5)t - (v + 1.5)
\]
\[
v \times t = v \times t + 1.5t - v - 1.5
\]
Simplifying this equation:
\[
0 = 1.5t - v - 1.5 \quad \text{(Equation 1)}
\]

### Scenario 2: Train is 1 km/h slower
If the train travels 1 km/h slower than usual, it arrives 1 hour later. The new speed is \( v - 1 \), and the new time is \( t + 1 \).

Thus,

Sebuah kereta api berangkat dari stasiun A ke stasiun B dengan kecepatan konstan. Jika kereta api bergerak 1,5 km/jam lebih cepat dari biasanya, kereta akan tiba 1 jam lebih awal. Jika kereta api bergerak 1 km/jam lebih lambat dari biasanya, kereta akan tiba 1 jam lebih lambat. Waktu tempuh kereta api tersebut dari stasiun A ke stasiun B adalah ... menit.

This math problem involves determining the usual time it takes for a train to travel between two stations, given different speed conditions. The problem requires applying the speed-distance-time relationship and solving algebraic equations.

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