Math Problem Statement

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Using divisibility properties, can you find the total number of factors of ( 422851 )?

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Solution

To find the total number of factors of 422851422851, we start by factoring it into its prime components and then using the properties of divisors.

  1. Prime Factorization of 422851422851: Let’s break down 422851422851 by checking for divisibility by small prime numbers.

    After testing, we find: 422851=29×14581422851 = 29 \times 14581 Then, we further factor 1458114581: 14581=29×50314581 = 29 \times 503 Thus: 422851=292×503422851 = 29^2 \times 503 So, the prime factorization of 422851422851 is 292×503129^2 \times 503^1.

  2. Calculating the Total Number of Divisors: For a number of the form p1e1×p2e2××pnenp_1^{e_1} \times p_2^{e_2} \times \cdots \times p_n^{e_n}, the total number of divisors is given by: (e1+1)(e2+1)(en+1)(e_1 + 1)(e_2 + 1) \cdots (e_n + 1) Applying this to our prime factorization 292×503129^2 \times 503^1: (2+1)(1+1)=3×2=6(2 + 1)(1 + 1) = 3 \times 2 = 6

  3. Conclusion: The total number of factors of 422851422851 is 66.

Would you like a more detailed breakdown of each step?


  1. What are the divisors of 422851422851 specifically?
  2. How can we generalize this process for any composite number?
  3. What is the significance of unique prime factorization in finding factors?
  4. How do divisibility rules help in the initial factorization?
  5. Can we determine the sum of all factors for 422851422851 as well?

Tip: Remember, each exponent in the prime factorization is increased by 1 to calculate divisors.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Divisibility
Prime Factorization
Factor Counting

Formulas

Total number of divisors formula: (e1 + 1)(e2 + 1) ... (en + 1) for p1^e1 * p2^e2 ... * pn^en

Theorems

Unique Prime Factorization

Suitable Grade Level

Grades 10-12