https://file.aiquickdraw.com/mathbot/file/1726068494831kxd42n9l.jpg

Let's break down the problem from the image:

- A tortoise makes a journey in two parts. It can either walk at **4 m/s** or crawl at **3 m/s**.
- If the tortoise **walks** the first part and **crawls** the second, it takes **110 s**.
- If it **crawls** the first part and **walks** the second, it takes **100 s**.
  
We need to find the lengths of the two parts of the journey.

Let:
- \( x \) be the distance of the first part.
- \( y \) be the distance of the second part.

For the first scenario, where the tortoise walks the first part and crawls the second:
\[
\frac{x}{4} + \frac{y}{3} = 110
\]

For the second scenario, where it crawls the first part and walks the second:
\[
\frac{x}{3} + \frac{y}{4} = 100
\]

Now, I will solve these two equations to find the values of \( x \) and \( y \).The two parts of the journey are:

- The first part is **120 meters**.
- The second part is **240 meters**.

Thus, the correct answer is **option (c)**: 120 m, 240 m.

Would you like more details on this solution, or do you have any other questions?

Here are some related questions to explore:
1. How do you solve simultaneous equations using substitution or elimination methods?
2. What are the advantages of using different speeds for different parts of a journey?
3. How can distance-time problems be modeled in real-life scenarios?
4. How can we extend this problem to multiple parts or different speed intervals?
5. What role do units play in ensuring accuracy in solving these types of problems?

**Tip**: Always check units in distance, time, and speed problems to ensure consistency throughout the calculations.

A tortoise makes a journey in two parts. It can either walk at 4 m/s or crawl at 3 m/s. If the tortoise walks the first part and crawls the second, it takes 110 s. If it crawls the first part and walks the second, it takes 100 s. Find the lengths of the two parts of the journey.

Learn how to solve a tortoise's journey problem where it travels in two parts at different speeds (4 m/s walking and 3 m/s crawling). This problem involves solving simultaneous equations to find the lengths of the two parts of the journey, suitable for Grades 7-9 students.

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