Math Problem Statement

A, B and C can finish a task in 42 days, 84 days and 28 days, respectively. A started the work. B joined him after 3 days. If C Joined them after 5 days from the beginning, then for many days did A work till the completion of the task?

Solution

Let's break down the problem and solve it step by step.

Step 1: Determine the rate of work for A, B, and C.

  • A can finish the task in 42 days, so A's rate of work is 142\frac{1}{42} of the task per day.
  • B can finish the task in 84 days, so B's rate of work is 184\frac{1}{84} of the task per day.
  • C can finish the task in 28 days, so C's rate of work is 128\frac{1}{28} of the task per day.

Step 2: Analyze the work phases.

  • First 3 days: Only A is working. In 3 days, A completes: 3×142=342=114 of the task.3 \times \frac{1}{42} = \frac{3}{42} = \frac{1}{14} \text{ of the task}.

  • From day 4 to day 5 (2 days): A and B are working together. Their combined rate of work is: 142+184=284+184=384=128.\frac{1}{42} + \frac{1}{84} = \frac{2}{84} + \frac{1}{84} = \frac{3}{84} = \frac{1}{28}. In 2 days, they complete: 2×128=228=114 of the task.2 \times \frac{1}{28} = \frac{2}{28} = \frac{1}{14} \text{ of the task}.

  • From day 6 onward: A, B, and C are all working together. Their combined rate of work is: 142+184+128.\frac{1}{42} + \frac{1}{84} + \frac{1}{28}. To add these fractions, we need a common denominator, which is 168: 142=4168,184=2168,128=6168.\frac{1}{42} = \frac{4}{168}, \quad \frac{1}{84} = \frac{2}{168}, \quad \frac{1}{28} = \frac{6}{168}. Their combined rate is: 4168+2168+6168=12168=114.\frac{4}{168} + \frac{2}{168} + \frac{6}{168} = \frac{12}{168} = \frac{1}{14}. So, when A, B, and C work together, they complete 114\frac{1}{14} of the task per day.

Step 3: Calculate the total work done.

  • In the first 3 days, A completed 114\frac{1}{14} of the task.

  • In the next 2 days, A and B completed another 114\frac{1}{14} of the task.

  • The total completed after 5 days is 114+114=214=17\frac{1}{14} + \frac{1}{14} = \frac{2}{14} = \frac{1}{7} of the task.

  • The remaining work after 5 days is 117=671 - \frac{1}{7} = \frac{6}{7}.

Since A, B, and C together complete 114\frac{1}{14} of the task per day, it will take: 67114=12 days\frac{\frac{6}{7}}{\frac{1}{14}} = 12 \text{ days} for them to complete the remaining work.

Step 4: Calculate how many days A worked.

  • A worked alone for 3 days.
  • A worked with B for 2 days.
  • A worked with B and C for the remaining 12 days.

Thus, A worked a total of: 3+2+12=17 days.3 + 2 + 12 = 17 \text{ days}.

Final Answer:

A worked for 17 days until the completion of the task.


Would you like any further details or clarifications?

Here are 5 related questions to practice:

  1. If B started working after 4 days instead of 3, how would it affect the total days A worked?
  2. What if C joined after 6 days instead of 5? How many days would A have worked?
  3. If A could finish the task in 35 days instead of 42, how many days would A have worked?
  4. How would the solution change if B could complete the work in 60 days instead of 84 days?
  5. What if A, B, and C all started together from day 1? How many days would the task take?

Tip: Breaking down a problem into phases and analyzing each phase separately is a powerful strategy in solving time and work problems.

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Math Problem Analysis

Mathematical Concepts

Work and Time
Rate of Work
Fractions

Formulas

Rate of work = 1 / time to complete the task
Total work done = Sum of individual work rates

Theorems

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Suitable Grade Level

Grades 6-8