To solve this problem, we need to determine the temperature corresponding to 116 chirps per minute based on the line of best fit shown in the scatter plot.

First, let's identify the equation of the line of best fit. We have two points from the line of best fit:

• Point 1: (100, 63)
• Point 2: (104, 64)

We can use these points to determine the slope $m$ of the line: $m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{64 - 63}{104 - 100} = \frac{1}{4} = 0.25$

Next, we need to find the y-intercept $b$ of the line using the point-slope form of the equation of a line $y = mx + b$. Using point (100, 63): $63 = 0.25 \cdot 100 + b \implies 63 = 25 + b \implies b = 63 - 25 = 38$

Therefore, the equation of the line is: $y = 0.25x + 38$

Now, we can use this equation to find the temperature when the chirps per minute are 116: $y = 0.25 \cdot 116 + 38 = 29 + 38 = 67$

So, the temperature would most likely be $67^\circ \text{F}$ if the crickets chirped 116 times in one minute.

Would you like further details or have any questions?

Here are five additional questions related to this problem:

1. How would you determine the equation of the line of best fit using more data points?
2. What is the significance of the slope in the context of this problem?
3. How can you check the accuracy of your line of best fit?
4. How would the temperature change if the number of chirps increased to 120 per minute?
5. What other factors could affect the relationship between cricket chirps and temperature?

Tip: When calculating the equation of the line of best fit, ensure that the points you choose accurately represent the trend shown by the data.