Math Problem Statement

Calculate \( \iint_S \mathbf{F} \cdot \mathbf{dS} \) where \( \mathbf{F} = \langle 4x^3z, 4y^3z, 3z^4 \rangle \) and \( S \) is the surface of the solid bounded by the hemispheres \( z = \sqrt{25 - x^2 - y^2} \), \( z = \sqrt{16 - x^2 - y^2} \), and the plane \( z = 0 \).

Solution

This problem requires calculating the surface integral of the vector field F over the surface S of the solid bounded by two hemispheres and the plane z=0z = 0. Here are the steps for solving it:

  1. Apply the Divergence Theorem: The Divergence Theorem states: SFdS=V(F)dV\iint_S \mathbf{F} \cdot \mathbf{dS} = \iiint_V (\nabla \cdot \mathbf{F}) \, dV where VV is the volume enclosed by SS.

  2. Compute the Divergence (F\nabla \cdot \mathbf{F}): The vector field is given by: F=4x3z,4y3z,3z4\mathbf{F} = \langle 4x^3z, 4y^3z, 3z^4 \rangle The divergence is: F=x(4x3z)+y(4y3z)+z(3z4)\nabla \cdot \mathbf{F} = \frac{\partial}{\partial x}(4x^3z) + \frac{\partial}{\partial y}(4y^3z) + \frac{\partial}{\partial z}(3z^4) Compute each term: x(4x3z)=12x2z,y(4y3z)=12y2z,z(3z4)=12z3\frac{\partial}{\partial x}(4x^3z) = 12x^2z, \quad \frac{\partial}{\partial y}(4y^3z) = 12y^2z, \quad \frac{\partial}{\partial z}(3z^4) = 12z^3 So: F=12x2z+12y2z+12z3\nabla \cdot \mathbf{F} = 12x^2z + 12y^2z + 12z^3

  3. Set up the volume integral: The region VV is the solid bounded by the two hemispheres: z=25x2y2(upper hemisphere)andz=16x2y2(lower hemisphere).z = \sqrt{25 - x^2 - y^2} \quad \text{(upper hemisphere)} \quad \text{and} \quad z = \sqrt{16 - x^2 - y^2} \quad \text{(lower hemisphere)}. Convert to cylindrical coordinates: x=rcosθ,y=rsinθ,z=z,anddV=rdrdθdzx = r\cos\theta, \, y = r\sin\theta, \, z = z, \, \text{and} \, dV = r \, dr \, d\theta \, dz The limits are:

    • θ[0,2π]\theta \in [0, 2\pi]
    • r[0,4]r \in [0, 4] (radius of the smaller hemisphere is 4, radius of the larger hemisphere is 5)
    • z[16r2,25r2]z \in [\sqrt{16 - r^2}, \sqrt{25 - r^2}]
  4. Evaluate the integral: Substitute F\nabla \cdot \mathbf{F} into the volume integral: V(F)dV=02π0416r225r2(12r2z+12z3)rdzdrdθ\iiint_V (\nabla \cdot \mathbf{F}) \, dV = \int_0^{2\pi} \int_0^4 \int_{\sqrt{16-r^2}}^{\sqrt{25-r^2}} (12r^2z + 12z^3) \, r \, dz \, dr \, d\theta This simplifies to: 02πdθ04rdr16r225r2(12r2z+12z3)dz\int_0^{2\pi} d\theta \int_0^4 r \, dr \int_{\sqrt{16-r^2}}^{\sqrt{25-r^2}} (12r^2z + 12z^3) \, dz

    • Integrate over zz first: 16r225r2(12r2z+12z3)dz\int_{\sqrt{16-r^2}}^{\sqrt{25-r^2}} (12r^2z + 12z^3) \, dz

    After this step, integrate with respect to rr and θ\theta. The symmetry of the setup may simplify the evaluation.

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Math Problem Analysis

Mathematical Concepts

Vector Calculus
Surface Integrals
Divergence Theorem
Cylindrical Coordinates

Formulas

Divergence Theorem: \( \iint_S \mathbf{F} \cdot \mathbf{dS} = \iiint_V (\nabla \cdot \mathbf{F}) \, dV \)
Vector field divergence: \( \nabla \cdot \mathbf{F} \)
Volume element in cylindrical coordinates: \( dV = r \, dr \, d\theta \, dz \)

Theorems

Divergence Theorem

Suitable Grade Level

College Level (Calculus III)