Math Problem Statement

Evaluate the surface integral ∫SF⋅ dS where F=⟨3x,−z,y⟩ and S is the part of the sphere x2+y2+z2=9 in the first octant, with orientation toward the origin.

∫∫SF⋅ dS=

Solution

To evaluate the surface integral SFdS\iint_S \mathbf{F} \cdot d\mathbf{S}, where F=3x,z,y\mathbf{F} = \langle 3x, -z, y \rangle, and SS is the part of the sphere x2+y2+z2=9x^2 + y^2 + z^2 = 9 in the first octant, oriented toward the origin, we use the Divergence Theorem.

Step 1: Apply the Divergence Theorem

The Divergence Theorem states:

SFdS=V(F)dV,\iint_S \mathbf{F} \cdot d\mathbf{S} = \iiint_V (\nabla \cdot \mathbf{F}) \, dV,

where VV is the volume enclosed by SS, and F\nabla \cdot \mathbf{F} is the divergence of F\mathbf{F}.

Step 2: Compute F\nabla \cdot \mathbf{F}

The vector field is F=3x,z,y\mathbf{F} = \langle 3x, -z, y \rangle. Its divergence is:

F=x(3x)+y(z)+z(y).\nabla \cdot \mathbf{F} = \frac{\partial}{\partial x}(3x) + \frac{\partial}{\partial y}(-z) + \frac{\partial}{\partial z}(y).

F=3+0+0=3.\nabla \cdot \mathbf{F} = 3 + 0 + 0 = 3.

Step 3: Set up the volume integral

The volume VV is the portion of the sphere x2+y2+z2=9x^2 + y^2 + z^2 = 9 in the first octant. The volume of the entire sphere is:

Volume of sphere: 43πr3=43π(3)3=36π.\text{Volume of sphere: } \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (3)^3 = 36\pi.

Since we are only considering the first octant, the volume of VV is:

Volume of V=18×36π=9π2.\text{Volume of } V = \frac{1}{8} \times 36\pi = \frac{9\pi}{2}.

Step 4: Evaluate the integral

Using the Divergence Theorem:

V(F)dV=V3dV=3×Volume of V.\iiint_V (\nabla \cdot \mathbf{F}) \, dV = \iiint_V 3 \, dV = 3 \times \text{Volume of } V.

V3dV=3×9π2=27π2.\iiint_V 3 \, dV = 3 \times \frac{9\pi}{2} = \frac{27\pi}{2}.

Final Answer:

SFdS=27π2.\iint_S \mathbf{F} \cdot d\mathbf{S} = \frac{27\pi}{2}.

Would you like a detailed step-by-step derivation of any part? Let me know!


Related Questions:

  1. What is the physical significance of the divergence theorem in vector calculus?
  2. How would the integral change if the sphere's orientation was outward instead of toward the origin?
  3. What happens if we extend the region SS to include other octants?
  4. How does the vector field F\mathbf{F} influence the computation of the integral?
  5. Can this problem be solved using parametrization instead of the Divergence Theorem?

Tip: Always check the orientation of the surface while applying the Divergence Theorem; it determines the sign of the flux.

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Math Problem Analysis

Mathematical Concepts

Surface Integrals
Divergence Theorem
Vector Calculus
Sphere Geometry

Formulas

∫∫S F ⋅ dS = ∫∫∫V (∇ ⋅ F) dV
Divergence of F: ∇ ⋅ F = ∂(3x)/∂x + ∂(-z)/∂y + ∂(y)/∂z
Volume of a sphere: V = (4/3)πr³

Theorems

Divergence Theorem

Suitable Grade Level

College-Level Calculus