Math Problem Statement

Find the supremum and infimum of the set S = {-1/n + (1 + (-1)^n)n^2 | n ∈ ℕ}.

Solution

The problem requires finding the supremum and infimum of the set SS defined as follows:

S={1n+(1+(1)n)n2nN}S = \left\{ -\frac{1}{n} + \left(1 + (-1)^n \right) n^2 \mid n \in \mathbb{N} \right\}

To analyze the set SS, let's break down the expression given for each nn:

  1. Expression Analysis: The expression for each element in SS is: 1n+(1+(1)n)n2-\frac{1}{n} + \left(1 + (-1)^n \right) n^2 where (1)n(-1)^n alternates between 11 (for even nn) and 1-1 (for odd nn).

  2. Cases Based on Parity of nn:

    • When nn is odd:
      • (1)n=1(-1)^n = -1
      • The expression simplifies to: 1n+(1+(1))n2=1n-\frac{1}{n} + \left(1 + (-1) \right) n^2 = -\frac{1}{n}
    • When nn is even:
      • (1)n=1(-1)^n = 1
      • The expression simplifies to: 1n+(1+1)n2=1n+2n2-\frac{1}{n} + \left(1 + 1 \right) n^2 = -\frac{1}{n} + 2n^2
  3. Finding Supremum and Infimum:

    • For odd nn, the values approach 00 as nn increases, but remain negative. Hence, the infimum of these values will be slightly below zero, depending on the smallest odd nn.

    • For even nn, the values become very large as nn increases due to the 2n22n^2 term. Thus, the supremum of the set SS will be the largest value produced by even nn, which can go to infinity as nn \to \infty.

    • Supremum: There is no upper bound, so the supremum is ++\infty.

    • Infimum: The infimum will be the limit approached by the values for odd nn, which is 00 from below. Therefore, the infimum of SS is 00.

In summary:

  • Supremum of SS: ++\infty
  • Infimum of SS: 00

Would you like more details or have any questions?

Here are some further related questions:

  1. How do limits help in determining the infimum and supremum in sequences?
  2. What would happen if we modified (1)n(-1)^n to something else, like a constant?
  3. How can we formally prove that a sequence diverges to infinity?
  4. What are some real-world applications of finding infimum and supremum?
  5. How would the solution change if the domain was restricted to only even or only odd nn?

Tip: When finding supremum or infimum, look at limiting behavior and consider cases based on parameters (like nn being odd or even).

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Math Problem Analysis

Mathematical Concepts

Supremum and Infimum
Sequences and Series
Limits

Formulas

Supremum and Infimum definitions
Limit of a sequence as n approaches infinity

Theorems

Limit properties of sequences
Behavior of sequences based on parity of n (odd/even)

Suitable Grade Level

Undergraduate level (Mathematics)