The exercise shown involves summation notation, and I can guide you through solving it.

For the first problem, the summation notation is:

$\sum_{n=0}^{4} (3n - 7)$

This means you need to substitute values for $n$ starting from 0 to 4, calculate the expression for each $n$, and then add them together:

1. When $n = 0$: $3(0) - 7 = -7$
2. When $n = 1$: $3(1) - 7 = -4$
3. When $n = 2$: $3(2) - 7 = -1$
4. When $n = 3$: $3(3) - 7 = 2$
5. When $n = 4$: $3(4) - 7 = 5$

Now, add the results:

$-7 + (-4) + (-1) + 2 + 5 = -7 - 4 - 1 + 2 + 5 = -5$

So, the correct answer to this question is -5.

Would you like to go over the other questions too?