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Buatkan jawaban untuk nomer 1 sertakan juga rumusnya

To solve the problem in question 1, we need to calculate the value of the summation:

\[
\sum_{n=-2}^{2} (n^2 - 3n)
\]

This requires us to evaluate the expression \( n^2 - 3n \) for each integer value of \( n \) from \(-2\) to \(2\), and then sum the results.

### Step-by-Step Solution

1. **Calculate each term in the summation**:
   - For \( n = -2 \):
     \[
     (-2)^2 - 3(-2) = 4 + 6 = 10
     \]
   - For \( n = -1 \):
     \[
     (-1)^2 - 3(-1) = 1 + 3 = 4
     \]
   - For \( n = 0 \):
     \[
     0^2 - 3 \cdot 0 = 0
     \]
   - For \( n = 1 \):
     \[
     1^2 - 3 \cdot 1 = 1 - 3 = -2
     \]
   - For \( n = 2 \):
     \[
     2^2 - 3 \cdot 2 = 4 - 6 = -2
     \]

2. **Sum the results**:
   \[
   10 + 4 + 0 - 2 - 2 = 10
   \]

### Final Answer
The value of the summation is:
\[
\sum_{n=-2}^{2} (n^2 - 3n) = 10
\]

Would you like further details on any part of this solution?

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#### Related Questions:
1. How do you calculate a general summation formula for any given range?
2. What if the expression inside the summation was different, such as \(n^3 - 2n\)?
3. How can summation be applied to solve real-world problems in statistics?
4. Can we use sigma notation for non-integer values of \( n \)?
5. What is the difference between finite and infinite summations?

#### Tip:
Always break down each term in a summation individually before summing them, especially when working with expressions involving both \( n \) and \( n^2 \).

Solve the summation problem \( \sum_{n=-2}^{2} (n^2 - 3n) \) with a detailed, step-by-step solution. This exercise covers key algebraic concepts and is suitable for students in Grades 10-12.

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