Math Problem Statement

Find the sum of first 20 even numbers.

Solution

The first 20 even numbers are:
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40.

To find the sum of the first 20 even numbers, you can use the formula for the sum of an arithmetic sequence:

Sn=n2×(a1+an)S_n = \frac{n}{2} \times (a_1 + a_n)

Where:

  • nn is the number of terms (in this case, 20),
  • a1a_1 is the first term (which is 2),
  • ana_n is the last term (which is 40).

Now, plug in the values:

S20=202×(2+40)=10×42=420S_{20} = \frac{20}{2} \times (2 + 40) = 10 \times 42 = 420

Thus, the sum of the first 20 even numbers is 420.

Would you like further details or have any questions?

Here are 5 related questions to explore further:

  1. How would you find the sum of the first 50 even numbers?
  2. What is the sum of the first 20 odd numbers?
  3. How can you derive a general formula for the sum of the first nn even numbers?
  4. What is the average of the first 20 even numbers?
  5. How would the sum change if we calculated it for the first 20 multiples of 3?

Tip: For any arithmetic sequence, understanding the first term, the common difference, and the number of terms will always help in finding sums easily!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Even Numbers
Summation

Formulas

Sum of arithmetic sequence formula: S_n = (n/2) * (a_1 + a_n)

Theorems

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Suitable Grade Level

Grades 5-7