Math Problem Statement

  1. What is the sum of the first 24 even numbers?

Solution

The sum of the first nn even numbers is given by the formula:

Sn=2+4+6++2n=n(n+1)S_n = 2 + 4 + 6 + \dots + 2n = n(n+1)

For n=24n = 24:

S24=24(24+1)=24×25=600S_{24} = 24(24+1) = 24 \times 25 = 600

Thus, the sum of the first 24 even numbers is 600.

Would you like a detailed explanation of how this formula is derived?

Related Questions:

  1. What is the sum of the first 50 even numbers?
  2. What is the sum of the first 30 odd numbers?
  3. What is the formula for the sum of the first nn odd numbers, and how is it derived?
  4. How can we prove the formula Sn=n(n+1)S_n = n(n+1) for even numbers using mathematical induction?
  5. How does the sum of even numbers compare to the sum of odd numbers for the same nn?

Math Tip:

The sum of the first nn odd numbers is always a perfect square: 1+3+5++(2n1)=n21 + 3 + 5 + \dots + (2n-1) = n^2.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Arithmetic Series
Even Numbers

Formulas

S_n = n(n+1)

Theorems

Formula for the sum of the first n even numbers

Suitable Grade Level

Grades 6-8