Math Problem Statement

5+8+11+14+.... S15=...

Solution

The given sequence is an arithmetic progression (AP), where the first term a=5a = 5 and the common difference d=3d = 3 (since 85=38 - 5 = 3).

The formula to find the sum of the first nn terms of an arithmetic progression is:

Sn=n2×(2a+(n1)d)S_n = \frac{n}{2} \times (2a + (n - 1) d)

Given n=15n = 15, a=5a = 5, and d=3d = 3, we can substitute these values into the formula:

S15=152×(2×5+(151)×3)S_{15} = \frac{15}{2} \times (2 \times 5 + (15 - 1) \times 3)

Simplify:

S15=152×(10+42)=152×52=15×26=390S_{15} = \frac{15}{2} \times (10 + 42) = \frac{15}{2} \times 52 = 15 \times 26 = 390

Thus, the sum of the first 15 terms is S15=390S_{15} = 390.

Would you like further details or have any questions?

Here are 5 related questions:

  1. How do you find the sum of a different arithmetic sequence, such as 7 + 10 + 13 + ... up to 20 terms?
  2. What is the 15th term in the sequence 5, 8, 11, 14, ...?
  3. Can you calculate the sum of the first 50 terms in an arithmetic progression?
  4. How do you determine the common difference in an arithmetic sequence if it's not given explicitly?
  5. How can you find the number of terms required for the sum of an arithmetic progression to exceed a certain value?

Tip: To quickly identify an arithmetic sequence, check if the difference between consecutive terms is constant.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Progression
Sequences and Series

Formulas

Sum of first n terms of an arithmetic progression: S_n = (n/2) × (2a + (n - 1)d)

Theorems

Arithmetic Sequence Sum Formula

Suitable Grade Level

Grades 9-10